This lady visited my school in the early 90's in Mumbai. I must've been 7. My classroom was one of the few she spent some time in. She picked random kids out, asked them to tell her their birth date and would proceed to tell them what day of the week they were born on, in like a couple of seconds. She even taught us some some simple maths shortcuts. I'll be damned if i remember any of them. I think I still have one of her books lying around. Absolute legend.
*Edited for clarity
So they asked her to figure out, in her head, what number multiplied by itself 23 times gives you:
As an experiment, start a timer and see how long it takes you to say this number aloud, let alone find the 23rd frigging root of it!!
It's so incomprehensible to me that someone could process it so fast!
I recently have been watching "Stan Lee's Superhumans" and they had a guy on who could do square roots, multiplications, and division in his head faster than people could type it into a calculator. While they didn't have him do anything to this level of complexity, they did have him do a few that resulted in high digits.
They looked into what gave him the ability to do it, and they found using an fMRI that the "math center" of his brain had mapped itself to the motor cortex, which allowed him to perform relatively complex mathematics at a subconscious level. Maybe this woman has something similar?
Link to the guy in question's wiki article: http://en.wikipedia.org/wiki/Scott_Flansburg
Oh, so he offloaded it to the GPU. Clever.
10/10 analogy, geek approved
By my calculation it's a 1 analogy.
1010/1010
10/10 would marry.
Could we do this to humans through science?
Probably not, at least not intentionally. Maybe in the future we might be able to encourage unusual cortical developments, but the way things stand right now the brain's wiring schema is far beyond complex, and the tools just don't exist.
Potentially if we can ever hijack neuron development we may be able to repair brain damage and generate our own specialized circuits. But neuroscience is pretty far off from there right now
If we lined up 100,000 people, kick them all in the head, maybe a savant will emerge.
Let's get a TRUE kickstarter going, Reddit!
Haha maybe not ethical, but I'll read your results.
Science at its finest.
WORLD STAH
Not only that, there are laws that discourage the kind of testing that would allow this to happen.
Should there be, though ? Why should we not be permitted to test the limits of our development ? There are possibly ethical arguments against brain-neuron augmentation, but I believe we can disregard them when potential gains are so high.
Perhaps we can, after a few decades of such testing, develop the equivalents of mentats in the Dune universe, who were essentially human computers. Utilize our brain's innate ability for parallel processing to the max.
Here is a part of the problem: Previously there HAS been human testing. Not for that but for human testing in general. It is widely considered unethical and there is a LOT of red tape to cut through in order to do any type of testing (medical animal testing first, for example), that is one of the reasons it takes years to produce a new medicine.
I should say that I am an armchair spectator. I don't know nearly enough to give a well formed response. Although if you do find this interesting, please look up bioethics.
Oooh, thank you for that link. This is a very interesting path to go down.
Anddddd down the rabbit hole we go!
It's an important question; however, I don't think we currently possess the technology to reach that level yet.
Yeah, I agree, we probably can't influence cortical development quite yet. We'll certainly be able to, soon. Much like the development of atomic weapons, human cerebral modification can be a game-changer.
The only problem is that the brain evolved over hundreds of millions of years to do very specific things in the most efficient way possible. It pretty much already runs at max capacity, so there isn't a whole lot that we could change to the pre-existing system. But, the idea of biochips is something that's already being worked on at the level of replacing modern implants, and brain-computer interface is another field that's just emerging in neuroscience (sloppily, but coming). All things considered, I think it's more likely that we'll continue using computers, but, who really knows?
Few things I want to mention is that the brain evolved over hundreds of millions of years to do everything as efficient as possible overall. The brain didn't specialize into mathematics per se. While it probably is running near max capacity overall, I wouldn't say it's running at max capacity in every area given that even this guy has technically advanced past "capacity" in arithmetic. So in the future it could be possible that we could specialize a brain for a more specific task, but it would be even more in the future before we could do that without losing efficiency in other areas. My best guess would be that we would probably try to recreate computers using a pattern/construction more similar to the brain than what we have now and then specialize that.
I agree in that with proper knowledge, we should be allowed to volunteer ourselves for experimental, invasive surgery.
If you mean human testing, then yes, but to be fair human testing is wildly restricted for essentially everything. However neuronal regeneration is one of the hot topics of neuroscience and medical research, and has been actively worked on for decades. Being able to regenerate cortical damage would revolutionize medical treatment for just about everything nerve damage to Alzheimer's or dementia. It's certainly not being blocked by legislation, we just don't have anything to test beyond animal models.
If we can prove that rigorous practice results in this result (very much the mathematical analogy to performing something until it is muscle memory) then telling people to simply practice mental calculations would be creating this change "using science".
It's incredible, really. We can develop all manner of invasive methods of forced weight loss to compensate for what is, relatively, a simple change in habits to produce the same results.
The question isn't "can we do this with science?". The question is, rather, can we do this surgically. Or, "can somebody make this change for me?". What would it matter if someone else could forcefully induce the change? It's not like one would utilize it anyways.
Well. I mean yes, neuroplasticity is the driving force behind practice improvement both cognitively and physically (muscle memory is a modification of the local nervous tissue). But there are quite a few limits on the change possible. Especially for those who have damaged tissue, or are just significantly deficient being able to add computational ability to the brain would be incredible medically.
That being said there is no habit in existence no matter how profoundly good for you that will allow you to regenerate your spinal cord. Likewise a damaged visual cortex may prevent you from ever recognizing the faces of your friends, distance or identity of objects, or completely destroy your ability to process the signals carried from the retina. And beyond fixing things, can you imagine the impact of being able to retune the brain? Psychopath to empath, major depression to motivated individual, for a lot of people struggling with mental disorders their biggest problem is themselves and habit based modification can only change so much.
Sorry for the rant, but people tend to discredit the petty outcomes of scientific advancements, while missing the broad implications that they would have throughout science.
And even if we understood it, there would still be many incredibly large technical hurdles between there and actually changing anything in a real, developed brain.
And that's what we're working on :)
[deleted]
Yeah! There are already some really brilliant scientists working on genetic modification, with very real successes. It's outside of my field, but we spend a lot of time working with genetics and at the current progression of things it may not be too long before we're administering gene treatments to cure hereditary disorders before they're inherited. This describes a treatment that lacks a lot of finesse, but allows the child's mitochondria to be inserted. Currently it's pretty controversial, but considering the fact that mitochondria do respond to the lifestyle of an individual I don't think that it would be all that far out for professional distance runners to sell their mitochondria. +1 to stamina and all that. Followed by more in depth modification as GMO's stop being held up like bogeymen.
i dream of this sort of thing
assuming there's no major downsides to such a link, imagine the possibilities!... or at least the novelties...
You don't fucking know.
It's sort of my thing, and one of the major topics in any developmental neuroscience course.
One day it could be a standard procedure.
Oh totally! Current neuromodulation is disturbingly basic, but the hope is that someday we will have to tools to modify brain circuits with the same level of accuracy that they form. There's just a yawning chasm of research that needs to be filled before then.
cry havok, and let slip the nerds of war
Man, the futures gonna be awesome.
Would that ever be allowed by the fda? I wonder how anyone would it is safe to try on humans after demonstrating it on mice.
You wandered in here a bit late haha. And yeah, it'll start with either implants or figuring out how to repair brain damage, but it wouldn't just be mice. Eventually it would be escalated through more complex models until the treatment was shown effective in non-human primates. Once it hits that point there should be a large enough body of work to begin an experimental stage 1 medical trial to evaluate the effectiveness in humans.
Anything that goes into the human body from a medical standpoint is very tightly regulated, which is good.
Yes, sorry I was browsing the top of the month for TIL and came into the convo very late.
I remember in a drug discovery and development class I took in undergrad the professor explained all the steps in an NDE pipeline. I guess I was just wondering how the hell anyone would prove (to the fda) this method works on mice before moving on to the next stage. With an efficacy study it seems to be more objective ; you would measure the size of an organ, the concentration of something, etc and show that a specific therapy works. But with something like this it's not as cut and dry because the end result is cognitive function. I guess behavior could be observed like it is for anti-depreseents, but it is just so novel because I can't think of one drug out there that is used to improve cognitive function.
Not a problem, just surprised me haha.
Now that I'm on a computer I can flesh it out a bit better, but you're right about treatment development being a bit different for some things in neuroscience. The underlying thing isn't really adding cognitive function, but replacing damaged function which is demonstrable. Lesion something obvious, like something in the auditory or visual pathway, and then if you can return function via implant or neuronal regrowth that's the first step in showing viability. Honestly, that alone would be earth shattering just for medical treatment, but fast forward a few years and it gives us an opportunity to add function rather than just rehabilitate. Which is fascinatingly enough a project that DARPA is going to try and implement by adding an "internal display" to vision.
There's a couple of drugs that seem to show cognitive improvements in certain disorders (neurotropics), but there's precious little evidence that they benefit healthy people at all. On the other hand, tCDS (transcranial direct stimulation) on the frontal lobes has a couple of studies now showing significant improvement in learning, which is promising.
HAS SCIENCE GONE TOO FAR?
Slide rulers hate him!
Nah. It's too near.
I say we haven't gone too far enough!
precision blunt force trauma?
Yeah man haven't you seen the documentary Limitless?
Well, it could backfire.
My motor skills are completely done by entirely different parts of my brain, and my motor functions SUCK.
Cave Johnson here...
Perhaps the Bene Gesserit could pull it off in many many generations
That's a Dune (frank Herbert) sci fi route. I don't see any other way though
Edit: which is speculative fiction. (Take what we know, what we are as peoples... Then extrapolate what 'could' happen if certain paths were followed).
Speculative science fiction is NOT fantasy. When done right, it is using what we know of ourselves as people, animals, masses/mobs following a logical (reasonably extrapolated from actual history and cultural anthropology) way that has naturally been attempted, if not succeeded in.
I would recommend the first Dune novel to illustrate this.
I would doubly recommend Isaac Asimov's Foundation series. The first at least.
Then there is the Ender's Game series which starts super speculative, then leads naturally into a study on cultural anthropology, then into socio-politics on a global scale.
Cheers.
http://en.wikipedia.org/wiki/Transcranial_direct-current_stimulation
No, there are no good drivers for the Asian models.
Brain CUDA
Too bad my brain has AMD and runs on linux...
At least youre FOSS
The firmware is proprietary though and the ACPI implementation he's running is a joke. He has to spend like 25% of uptime in S3 sleep otherwise he starts oopsing in a day or two.
I'd just like to interject for a moment. What you’re referring to as Linux, is in fact, GNU/Linux, or as I’ve recently taken to calling it, GNU plus Linux. Linux is not an operating system unto itself, but rather another free component of a fully functioning GNU system made useful by the GNU corelibs, shell utilities and vital system components comprising a full OS as defined by POSIX.
Richard Stallman? Is that you?!
You could just use OpenCL instead of being upset that you can't use a closed source proprietary API.
No OpenCL for legacied AMDs, though (IIRC).
I also have trouble getting refill ribbons for my 9-pin dot matrix... is this really a problem? ;)
I'm still running on Windows 69
Unfortunately it seems that Microsoft will skip NT 6.9. Windows 8 is Windows NT 6.3, Win10 will apparently be NT 10.
Can you SLI it?
That was a Star Trek level analogy for an overly complicated explanation! UUUUUUUUUUUUUUUUUUpvote
More like using one of those PhysX cards.
PhysX is run on the GPU
I know - they used to have dedicated cards though.
She looks kinda old, probably has a SNES FX chip..
Anyone remember x87 FPUs?
Bet he has a 980.
Math Co-Processor!
Source: my 486SX had this
Now... SLI.
Bohemia, take note of this!
This guy is triple sli-ing 980s and here I am with Intel HD graphics.
multi threads genetic modified brains would be something incredible to aim for 22nd century.
Let's hear it for motor cortex. I slipped on the stairs the other day, my hand flew out and caught the edge of the stair before I knew what was happening. My brain figured what muscles to hit when, to hit a target while moving.
It is really fascinating! The other day I was tossing my keys around while standing up and I mistakenly tossed them at an arc over my back. My brain was on it though, because even though I was telling myself that they were lost, my hand reached behind my back, completely out of sight, and caught the keys with seemingly no effort at all. It was then that I took a moment to reflect on how fascinating the human body was and how we should appreciate the several tens of thousands years of evolution that forged us.
how precisely it can calculate the exact arc it took with the weight and force used instantaneously
even knowing all the variables, to calculate it manually isn't anywhere near so simple.
Exactly! These extraordinary things happen on a subconscious level but are only taken for granted. Truly fascinating though.
I have recently seen an increase in my reflex. When I drop something and reach out to grab it, it's almost as if my brain does it before I consciously even apprehend that I dropped something.
...Or maybe the initial panic of dropping something just clouds my view.
That's interesting.
Pretty sure you cannot, I think its something he was born with.
Maybe it's Meybelline
She's gonna stop buses.
Nope! It's developmental!
Why can't I just learn math again with a different part of my brain? I'll just drink like a stem cell shake for breakfast
Well, if you're open to the possibility of brain damage...
2 math centers has got to be better than one math center. I see nothing going wrong.
The stem cells might put a dick in their brain instead of a maths centre. Or something. I am not a biologist. Mercifully.
...i'll be your biology subject anytime
blunt force trauma has been known to give new links within the brain
i mean, sure, you'll certainly have some brain damage, but you might be able to see numbers and stuff.
psychadelics?
Apparently the show presented his ability as something innate he was just born with, but you can definitely learn to use the visual and motor processing parts of your brain for mathematics. A lot of mental calculators do this by learning how to use an abacus. They then create a mental model of an abacus in order to do calculation in their mind more effectively. Getting good at that eventually allows people to do shit like this.
Pretty sure you, your colleagues, and the rest of the world would've heard about it by on wow.
Hook him up to the Matrix so he can mine bitcoins for Mr. Smith.
So, was there any detriment to his motor skills?
Apparently not? If there was they didn't mention it in the show.
I can't wait until we're able to figure out how to map all of our math centers to our motor cortexes.
I cannot believe that isn't how we developed since it makes doing math easier by seemingly an almost unimaginable amount. I wonder how powerful computers might be if we could all do math at this level...
We didn't need complex math much for the last several million years. It was kind of on the backburner.
There's a British guy who can do this as well as learn languages in a few days. He has a form of synesthesia where he experiences numbers as visual hallucinations. He can then navigate this visual experience and do complicated math without having to memorize log tables or do some of the other things that human calculators have to do.
May wanna check on that, I've read several articles where a lot of people that claim that have been proven frauds. Not to say it doesn't exist.
Here's the guy. Apparently he's been tested by a bunch of neuroscientists to see if he was just memorizing shit they were pretty sure he had synesthesia.
http://en.wikipedia.org/wiki/Daniel_Tammet
There's a whole section in the wiki article about the test that were done on him. Most indicate that he most likely has synesthesia.
I wonder if that means he has an unusual connection between movements and doing math. Like moving or imagining to move a certain way is part of his process of coming up with a solution
i wonder if such a mapping involves any drawbacks
I wonder to what level of connectivity can you give different areas of the brain, before it manifests some form of disability?
I can do this ^(with single digit numbers)
Edit: who the fuck taught Reddit order of operations?
This made me think of this episode of Radiolab I just listened to.
It's about a guy who can 'play' several pieces of music in his head simultaneously and keep track of each one.
They tested him with three different pieces of music with different key signatures, tempos, and starting at different times.
They told him to start playing each song in his head, and at the same time started playing a recording of the song (that he couldn't hear).
At some point in the middle of all 3 songs playing they told him to stop and he was able to sing exactly where he was in each song and he was in sync with each of the recordings that had been playing.
Not sure if I explained that in a confusing way; hopefully it makes sense.
I wonder if there's any downsides to that, like he can't move or he's less coordinated while he's calculating something.
So is this like an evolutionary trait/mutation?
When I was in school I had terrible eyesight and a very good affinity for math, coupled with a school that liked to use a program called '10 quick questions'. Since I was in top set, we usually had the setting for whatever we were learning maxed out and the time allowed for each question being 6 to 8 seconds. Bear in mind this same program was used throughout the school, from ages 11 to 18, and if the questions were ever too difficult for the majority of the class the time would be increased to a maximum 10 seconds. The scores out of 10 would then be collected, but I don't think they were used for anything other than to see if mental arithmetic improved.
Anyway while everyone tried to use their precious seconds to write stuff on paper, it took me a few seconds to read the thing. Me being competitive I adapted, started trying to visualise these problems in my head and started noticing patterns very quickly, patterns that are difficult to explain.
My point is I ended up massively increasing my test scores not only in the program, but in the actual exams too. I ended up being able to 100% exams in 18 minutes at my quickest, with an average of 22, for a 90 minute exam - if I chose to answer the stuff in my head. In my final exams at school before going to uni I ended up being one of the few kids in the country (England) to get 100% in an exam that trended on Twitter for being so difficult (I personally think everyone whined because they only revised what normally came up).
Now I'm at uni studying maths and physics, while working at McDonald's to pay for my house, and my colleagues love asking me questions about quantum physics, space etc. I love it when someone whacks the calculator out and asks me a question they think would be too difficult to do in the head just to see if I can do it, and I end up beating them before they type it in.
That's insane.. I assumed she was on the autism spectrum and considered a savant. Either way, Definitely not a normal brain to be capable of that.
google fmri dead fish
i'll be waiting
Just.... How...
To help make it more comprehensible, there is likely a pattern that arises. You're trying to comprehend her literally calculating the math in that way that you've been taught or in a way that a computer would compute the numbers.
In reality, she likely had memorized thousands of patterns that numbers follow when you do certain things to them, kind of like how a rubik's cube expert can look at the cube and then solve it blindfolded.
So when given a certain large number, and some calculation to do with it, she could then "simply" find the result by knowing what pattern the numbers will fall into.
The pattern for a cubed root is pretty straight forward. If you get a friend to take a 3 digit number, XYZ, and cube it on a calculator and give you the answer. You can mentally work it out quite quickly.
The only pre-requisite is to know the cubes of numbers 1 - 9.
For example, take 119,823,157. As it ends in a 7, we know straight away that the original units number must be a 3. (3³=27). The million value, 119, is above 64 (4³) but below 125 (5³) so the number begins with a 4. The initial number is therefore 4Y3. 119 is far closer to 125 than 64, so the tens number is either 8 or a 9. A decision needs to be made whether it's 483 or 493 but with a bit of practice you'll get a feel of which one to go for (493).
That's pretty simplistic compared to this ladies skill of 23rd root. However, I suspect it's using a similar idea regarding patterns. The cubed root approach above can be done in 3 or 4 seconds with a bit of practice even though the computation you are doing in your head is not a cubic root calculation.
See guys, its just that simple
Now a 24th root. . . fuggetaboutit.
Jake Barnett quickly shows how he visualizes the addition, subtraction, multiplication and division of the number 32 in a ted talk on youtube. https://www.youtube.com/watch?v=Uq-FOOQ1TpE at 1:20
.
seems amazing but not simple for me as I read this many time and can not under how it work...I admit I am a litter bit ...
Walk in the park, I do it all the time.
wow. that was cool. never knew it worked like that but makes sense that it dsoes
Technosorcery.
the same technique applies for the 5th root as well. and the pattern for the last digit is even simpler.
might be that just counting the number of digits in the given result narrows down the possibilities when talking about integers raised to the 23rd power...
we also have to know exactly how the question was posed. did it came out of the blue ? or was it as a part of set of questions that were agreed upon beforehand?
this makes the story totally different from the M.O. point of view while the media can still celebrate on it.
if you are interested - check out the Arthur Benjamin books and lectures - tons of stuff like that
Correct the 5th Root results in a 1,2,3,4,5,6,7,8,9 pattern, whilst the 7th Root repeats the 3rd Root pattern; 1,8,7,4,5,6,3,2,1. This would continue throughout the odd numbers. Even numbers are harder because 4² ends in 6 as does 6², for example.
But you are right, the ladies skill is impressive even if a feat of memory. If it was a random question it's incomprehensible how she done it. However, if she knew she was going to have to work out a 23rd Root, then it's comprehensible as an extraordinary feat of memory.
So she just happened to know the value of 2^23, 3^23, 4^23, etc up to 9^23? Lol.
8,388,608 and 94,143,178,827 are the first two... I can't imagine remembering the number for 9^23
And the answer to her problem was 546,372,891^23 ... not exactly a small number. Absolutely unbelievable.
No, you missed the point. There are other patterns. Straight away you can work out the last digit as (any number that ends in 2)²³ will always end in 8, (any number that ends in 3)³ will end in 7 etc. There are patterns the whole way through that you can learn. If you read the article this lady had exceptional memory skills, better than I could ever hope for because I could never memorise the numbers and patterns involved.
A simpler example is try multiplying 15*10 in your head. I guarantee you don't, you know the pattern is to add the 0 to the 15 to get 150. Our brain works with patterns like this.
I had to read this many times to understand what you meant exactly, but now I understand it. Very clever! So can you give me an example besides the final digit? It seems you could use it with the first digit too. But beyond that... what can you do? She had to come up with 546,372,891 not just a single or double digit number.
Is it that she knows like the 126th digit is a 7 or whatever, then she knows the 3rd digit of 546,372,891 is an 8? Something along those lines? Or is that a terrible example
I was going to post something very similar. For the middle number, learning how to estimate is a little bit more complicated, but it is still something you can learn in an hour or two max.
For her record, she had a 201 digit number, which gives a 9 digit answer. The first two digits range from 54 to 60. The last digit of the answer is fully determinable by the last digit of the given number.
It is possible to expand the tricks used in the 3 digit example to the 9 digit problem. The last 3 digits can be found in a similar manner. Using the last 4 digits of the given number, you can determine the last 3 digits of the answer, except when the number ends in 5 or 0. But in those cases, the problem just gets significantly easier.
The first 2 digits are trivial to find, and expanding that to 3 digits is not difficult at all. If you memorize the first 3 digits of the the answer for each number between 54^23 and 60^23 (which you have to learn anyways to determine the first 2 digits), you can use that to estimate the 3rd digit of the answer in the same way you determined the middle digit in your example.
Actually, now that I think about it, you can use that to accurately estimate the next 2 digits, if you just memorize the first 4 digits of 54^23 to 60^23.
That's memorizing 7 four digit numbers to get the first 4 digits of the answer. Then you have to memorize about 800 numbers to get the last 3 digits, but there are plenty of patterns within that to cut that task into more manageable parts.
To get the middle 2 digits of the answer, you would have to come up with something else. The easiest way I can think of is to expand upon the trick for the first number. By learning the first 5-6 digits of the 23rd power of every number between 540 and 610, you can use that to fairly quickly determine the first 6 digits of the answer.
So in total, you would have to memorize 65-70 six digit numbers and 800 three digit numbers. Then you have to be able to recall them within 50 seconds. It's an impressive feat, but I think if anyone cared to set a record for solving 23rd roots of 201 digit numbers, you could accomplish that within a couple months of work.
Oh yeah. I did that on 8 seconds. Take that insanely smart Indian lady! /sarcasm
I hate maths but that was really nice
I'm just amazed I followed this explanation with complete comprehension. Since becoming a tutor, I'm understanding concepts so much better. That whole explain to understand thing really does work!
Except you started with a specific number and she had 201^2 numbers to choose from.
Also if you go the other way round 567891234²³ has 201 digits, 456789123²³ doesn't as doesn't 678912345²³. And if you compare 567891234²³ and 567891235²³ they change by about one 20 millionth, so it's less than 200 million possible numbers that land in the 201 digits and they all got 9 digits with the first one being a 5 or a 6 (I checked 499999999, 6000000 and 7000000).
for a very similar take, see this cool ted video: www.ted.com/talks/arthur_benjamin_does_mathemagic?language=en
90s_kid_approves.webm
Pretty much what this guy said, I mean what she did is fucking amazing but his logic applies to a lot of things in life, complicated things can become simple if you find the proper algorithm in which to work them.
[deleted]
That's the whole concept behind Asimov's Psychohistory. If you haven't read the Foundation series I recommend it as hard as you can recommend anything.
I'd second that recommendation
The Hugo Awards created a "Best All-Time Series" award several decades back. Asimov told his friend that they had finally figured out a way to separate Lord of the Rings and put it on the pedestal it deserved. The Foundation trilogy won.
Arguably the greatest science fiction ever written
I still don't understand the fascination with LOTR. Very rich world, very thin story.
The world and characters were really well designed by the standards of his era. You'd need to go into more detail as to why you thought the story was thin.
I'd agree with anyone however that Tolkien's writing style is boring by today's standards. Unless it's being compared to Robert Jordan, LOTR moves extremely slowly.
The fascination comes from the fact that most current day fantasy comes from the ideas of Tolkien's rich world. What I mean is that the rich world is the reason that it was and is so successful.
The greatest evil exists and there's no way we can stop it.. except maybe if some little people do something impossible while a totally unrelated battle takes place in which the outcome doesn't matter, yet they win that battle anyway, because conveniently a bunch of ghosts decided at the last second to side with somebody for no reason.
Relevant
I third that recommendation.... Unfortunately, no one can predict the Mule.
thats not really what psychohistory is. its that you can predict characteristics of large and complicated systems because the variance of the system is small compared to its size.
The concept of psychohistory is about the only interesting thing in that series. Which is still really cool. But the dialogue and plotting is something straight out of campy sci-fi b-movies from the 60s.
Well Foundation was published in 1951, so it's likely all those movies were influenced by Asimov.
And somehow, being aware of that fact doesn't make the text any more enjoyable. Disappointing, right?
The dialog is certainly campy, but I don't think the plot at all is...
The moment he called a character the Mule and then 200 pages later built up an enormous reveal about the character being sterile, he lost me forever. It's just not good plotting, sorry. Maybe the problem is that I read it for the first time as an adult.
The fact that it's the basis for modern sci-fi doesn't make it any more enjoyable. I'm glad I read it in order to see his ideas and gain a broader understanding of science fiction as a genre, but it's just not well-written by any modern standard.
Your'e kinda reducing all of the plot to a single reveal, which, granted, wasn't that much of a shocker. My point is that the surprise identity of the Mule is just one small aspect of the plot.
No, I'm using an example. The whole thing is written that way.
I mean, I guess we can agree to disagree, but one "shamalanish" reveal doesn't to me, prove your point. I didn't come away from Foundation feeling that the plot was campy, though again, the dialog definitely was.
/r/cliodynamics
http://www.angelfire.com/un/corosus/books/Asimov_the_foundation.pdf would this be it?
Meh. Read them but wasn't that impressed. I can see how he influenced a lot of science fiction but his own writings are pretty bland. If he was published today under a different name people wouldn't pay the books much attention.
That's basically the philosophical theory of hard determinism. It's pretty depressing, because if true it means that everything is essentially predetermined and there is no such thing as free will
[deleted]
I've thought about this a lot in the past few years. I don't know a whole lot about quantum mechanics so I'm asking this sincerely... are you saying that there are some aspects at some level that are purely random? If you knew all variables from all states would it still be impossible to determine what would react and how? This has been my only hope that free will actually exists so I'd really like some good news here!
[deleted]
Well since they're acting according to wave equations they're 30% left and 70% right simultaneously.
Your personal wave equation has you currently on the moon, just with very low probability.
It's not a binary though, it's both right and left until you observe it. This is the basis of Quantum Computing, instead 1 and 0 you have 1, 0 and both 1 and 0.
This is true. I deigned to leave that out for the beginners' sake, but yes, there is a superposition of both at the same time until the wave is observed. This is what Schrodinger's cat tells us about. Unobserved, the wave function occupied both points, but once observed, the function collapses and occupies just one point.
I'll go ahead an ask the obvious...what would act upon the particle to ever make it fork left? It's hard to wrap my head around the idea that cause/effect is completely suspended here. Could there simply be something we don't understand yet that makes it fork left occasionally?
Well, my explanation was a bit simplified, and therefore flawed. Here's how it really is:
While unobserved, the particle exists in a superposition that has a probability wave of being 70% right and 30% right at the same time. Once observed, that wave function collapses, and the particle chooses which state it's in based on probability. Think Schrodinger's cat. Until it's observed, the cat is both dead and alive, and it's not until the cat is observed that it chooses a single state to be in. Now, it may be that the cat has a probability wave of 99.9999% alive and 0.0001% dead, but it is still in a superposition of both dead and alive.
Ok, I think I'm getting there. It's not a matter of a marble driving down a hill and being coerced left or right, it's just left or right once observed, yes? I think what I'm missing here is the momentum or linear progression from one state to the next. Marble is on top of hill -> SOMETHING HAPPENS -> marble is observed at the end of the left or right path. Alive cat goes in box -> configure poison, etc. -> SOMETHING HAPPENS -> observe alive or dead cat. I keep getting hung up on the 'something happens' part. Does that part simply not exist? Thanks for taking the time to explain some of this!
I think this question is straying into areas that I'm not qualified to answer, so I'm gonna say I don't know. Sorry! I hope you found this informational, though. If you wish to learn more, I'm sure /r/askscience can help guide you to the right resources.
Since you seem to know something about it, perhaps you can answer the question I've been carrying around ever since I first read about this:
How can anyone say with any certainty at all that behaviour is 'probabilistic' rather the 'deterministic' given that it is certainly impossible to recreate identical conditions? How is it possible to rule out effects that we do not yet understand or are not yet able to detect which would determine the outcome?
Because from the perspective of a half-educated (when it comes to physics) pleb, this looks to me like scientists giving up the search for the deterministic cause.
[deleted]
The quote you've put in there makes absolutely no sense to me at all. It seems to be begging the question rather than explaining how we've come to know that results are probabilistic rather than deterministic.
I do not understand why the fact that we are much better at controlling our environment (and therefore experimental apparatus) than we were in the past suggests that we've come anywhere near the maximum level of control or understanding.
My other problem with this is that even if you could control EVERYTHING in an experiment, you still wouldn't have identical conditions because you have moved in time. If there were a way to go back in time and run the last second again, a probabilistic universe would certainly be different, right? But a deterministic one would be identical. We can't run this experiment as far as I know. Again, not trying to troll, just trying to understand a little better.
Basically what arahat108 said.
:( still don't get it.
If you want, you can do some research on the experiments that have been conducted. I'm not learned enough, myself, to fully answer your question. The experiment that arahat listed (the pendulum one) would be a god place to start.
Essentially yes even if you knew all variables involved, the behaviour of quarks cannot be predicted. Einstein actually disagreed with this in his famous book "God does not play dice" but he has since been proven wrong.
Keep in mind that the lack of determinism does not necessarily prove that free will exists. You have as much control over something that's random as you do over something that isn't.
Yeah, and I think hard determinism has fallen out of favor with the majority of philosophy, I think compatabilism views tend to be more popular. I was just pointing out that that's basically what OP was referring too.
but who's to say that in the future physicists won't use 100% deterministic models ?
Free will is an illusion. We act based on impulses and what has previously happened to us. Our brains are programmed to respond in specific ways to specific stimuli
Not if you use a compatibilist definition of free will http://en.wikipedia.org/wiki/Compatibilism
Though yeah many people consider that not free will. But personally I wouldn't consider adding random factors to the process as being particularly desirable.
Determinism means your actions are a direct result of who you are - your character, your preferences, your thoughts. Add randomness and you sometimes do stuff without a reason. You might be argue that makes you more free but I would argue that it wouldn't have much to do with will.
For not compatibilistic definitions I agree with J.J.C. Smart http://en.wikipedia.org/wiki/Dilemma_of_determinism#Deterministic
The problem is that there is a fundamental limit to how much we can know. It is called Heisenberg's Uncertainty Principle.
It basically says that we can never know exactly both the momentum and location of a particle simultaneously.
This means that at the small scale, not everything can be predicted.
That's only when working with physical particles. In the virtual world you CAN know both at the same time.
You just need to know the starting state of the universe
But he was talking about the real world...
You can't answer a question by changing the question. I could also have said what you said.
No. The Heisenberg uncertainty principle crumble to bits if we can know the start conditions. If we can know the start condition of the real world, we could know the precise number of air molecules you will be displacing tomorrow.
Nope, there is a fundamental randomness on the quantum scale.
Small uncertainties in the beginning will have a large effect on the future. http://en.wikipedia.org/wiki/Chaos_theory
You will never know anything about the start conditions unless you make them up
Edit: Even if you know the starting conditions, nature will almost never follow your predictions due to the fundamental randomness.
Meh. We will probably find our way out of that - Random is almost always not random.
The only way out AFAWK is to make our own world i.e. The Matrix.
Well, he thinks he's talking about the real world. But there's a number of theories out there that suggest that we may be living in a simulation of some sort ...
(Of course, such theories are rarely falsifiable so they're not really scientific. But that doesn't mean that one of them might not be correct!)
Oh and the Uncertainty Principle arises due to float point inaccuracy or some arbitrary limit set by our overlords? Lol.
The Matrix would be cool but it's best to ignore it, really.
Not exactly, he's talking about simulating the real world. Big difference
Yes but you will need some sort of starting state.
Finding that is where the Heisenberg Principle craps on the problem.
E.g. to "see" an atom, you would have to send in an EM-wave with a very small wavelength and wait for it to bounce back. Great, you know the position. But that EM-wave had a very high energy due to the small wavelength and has given the atom some velocity in an unknown direction.
Edit: There will always be an uncertainty. It will add up over time. http://en.wikipedia.org/wiki/Chaos_theory
If you are simulating it then surely quantum effects should come into it?
You would a computer that could simulate every fundamental particle of the universe. Unfortunately, that takes a computer the size of the universe
Our universe is that computer simulation. Hi fellow sim.
a/s/l?
15f cali
send me a few hundred bucks so I can come visit you. make check out to cash or send cash.
[deleted]
I replied just from the nostalgia of seeing it. The joke was the additional scam. "Hot chick" will come visit you (send some random gif of chick and the po box) just needs couple hundred for gas, needs vacation anyway, yadda yadda. You just played scratch off and lost a couple hundred bucks.
But if you just want a simulation to determine the ultimate question of the universe, you just need a computer the size of the Earth.
Mostly Harmless
Hm. Tricky.
I'm just picturing in my head what hard drives looked like in 1975 and I'm thinking that with enough time and technology it could be done in less space.
There are theoretical limits on informational and computational density. We are so far from them that we might as well not be computing at all; but they do exist.
If we tried to use computers as we know them to do the modeling.... It would require an infinite number of universes all doing nothing but being filled with computers calculating the universe.
And it would still be slower than the actual universe by a few orders of magnitude.
I think the key words here are "computers as we know them."
Yes. Even, however, assuming that we could achieve functionality valid quantum computing and compute at the theoretical limits, we'd still need multiple universes. Even with spatial manipulation to bypass the limit of
cfor networking purposes.I'm going to cling stubbornly to the notion that one of my distant descendants will have a pocket iUniverse.
One of my distant descendants -- by which I mean a variation of my own uploaded consciousness -- will have access to multiple universes.
So there.
No, as kingphysics said ... the Heisenberg Uncertainty Principle nixes that idea.
... to completely model a grain of sand.
Unless you have quantum computers.
minority report (and probably many other sci fi stories)
You dare speak the profane rite by which is invoked the Demon of Laplace?!
You monster!
False! There's our old friend Mr. Heisenberg to contend with.
Shhh, now everyone knows my programming secrets!
This.
Correct me if I am wrong, but I thought the word algorithm referred to an exhaustive process used to find a solution that is guaranteed to work given enough time, whereas a heuristics were techniques that use patterns and other such things to arrive at a solution faster.
Can confirm - YouTube + weed + 5 hours and I can now "solve" a rubix cube in roughly 50-60 seconds. It varies by hoe it's been mixed.
Has anyone figured out the algorithm for solving bat shit crazy?
you guys saw that Morgan Freeman special too, huh?
how do I find more algorithms
Does that logic apply to banging Scarlett Johansson?
Except for some problems that are easy to check the answer to but hard to efficiently calculate in a general way.
Like a cross country trip to visit 126 cities. You want to reduce total gas cost. What's the order in which you should visit the cities and go home?
I still tell people this story almost 6 years later because I was so impressed by it. Obviously not nearly on the same scale as this person, but the company I used to work for I was in the IT department and we had just gotten in a bunch of those USB cellular cards and we're starting to assign them to users. The CEO of the company comes down one day and asked me how many of them we have, it was like 189 or something, and then he ask me how much we have to pay for each one monthly, it was like $47. Within a split second of me saying $47 he rattled off how much it was costing us for all of those monthly, so 189 x 47. It really was quicker than the snap of a finger, I was floored. I've always considered myself to be a quick thinker, but the even a problem like that would have taken me a couple seconds to solve in my head. People can do some amazing things.
Algorithm is such a nice word
Wait so if something hard comes up and I figure out how to solve the problem , then I can solve the problem? No fuckin way
yeah when you put it that way its really not that impressive
stupid bitch
Thanks, I laugh a little harder than I should lol.
That's fucking hilarious.
I love you
Aaaaand I woke the kids (again) with my night laughter...
What a casual amirite!
[deleted]
starts sentence with straw man, fails to see the joke
Gotta love pseudo-intellectuals! me so smart!
Downvotes because the guy was clearly kidding.
i dont even know how to SAY that number let alone calculate it. quadzillions?
http://en.wikipedia.org/wiki/Names_of_large_numbers
Somewhere between a Vigintillion and a Centillion, I imagine. But I have no idea how to figure it out.
EDIT: Looked further down. Looks like somewhere between a Sextaguntillion (10^183) and Septuaguntillian (10^213)
Sextaguntillion is my "bedroom" name.
I play AdventureCapitalist so I know these numbers
I think it's a Cunnilingustillian.
Something about reptillian humanoids...
There are tons of tricks anyone can do. I can tell you immediately without even thinking about it, that the last digit of the root can't be 0, 2, 4, 6, or 8 since any power of those will also be even. I also know the last digit can't be 5. Can't be 3, since 3^4 is 81 so 3^24 also ends in 1 so 3^23 won't end with 1. Can't be 7, since 7^2 is 49 so 7^4 ends in 1 so 7^24 ends in 1 so 7^23 won't end with 1. Can't be 9, since 9^2 is 81 so 9^24 ends in 1 so 9^23 won't end with 1. So, by only looking at one digit, I can already narrow down that the last digit of the answer is 1. There's a lot of little tricks that can help simplify problems like these, though it's still a horrendously large number, so it still takes a good amount of raw brainpower to get the other 7 digits.
Here's what it looks like
I don't think that logic falls to roots, because of hard it is to calculate a square root. Let alone a 23rd root.
She wouldn't be calculating the square root. She would be applying her knowledge of patterns created in numbers when a square root is calculated.
Let's say that when you take the coinclink^tm of a number represented in base-10, every instance of the number 8 becomes 5, 9 becomes 3, 6 becomes 2, etc. She could just go down the line of numbers and change each number to get the result.
It wouldn't be nearly that simple but if you had knowledge of real mathematic patterns like this, you could do it.
Richard Feynman, in his book "Surely You're Joking" has an a anecdote about that. Before electronic calculators were invented some guy tried to sell him a mechanical calculating device. At first the device was faster than Feynmann, but after the second or third iteration Feynman was faster, because he understood the patterns of how numbers work, and the calculator was just using brute force.
Some people process some things differently.
Saying 'she likely had memorized thousands of patterns that numbers follow' is idiotic.
I dont know is a much better answer.
I had a math professor in college that would write on the board with both hands simultaneously, took his sabbatical at the CIA cryptography center, and just through-and-through the most intelligent person I have ever met. I don't know how it even came up, but one day in class us students gave him any random number and he would within seconds tell us the log (I think base 10, may have been base e) of that number to 5 or 6 significant figures.
And He could do it pretty much just like you explained: He conceptually knew how numbers reacted when passed through the logarithmic function, especially as they converged to the next "base" - so like, if to start I know that log(10)=1 and log(100)=2, and I also know that as n increases from 11 to 99 the log function output's percentage difference decreases [e.g. log(12)-log(11)=~.037, but log(99)-log(98)=~.004), then I can interpolate from there..... Yet he was doing it while being able to not just "guestimate," but give actual accurate answers.
I think you're right for the most part, but the Wikipedia page claims she started doing this at the age of 3 even without any formal education! I'm sure she improved vastly since age 3, but no formal education is just stunning.
Or perhaps, formal education is what is dumbing us all down! ;)
Ah yes, in retrospect it's really quite simple, just like solving a Rubik's Cube blindfolded.
Well since you summed it up so simply, how anybody can't do this is beyond me....
While probably not easy to do, I presume it's possible to program a computer to do the same correct? I'd assume you might faster results for specific calculations.
I hate being that guy, but solving a rubik's cube blindfolded requires around 3 algorithms, which can be learned in around 10 minutes. The rest is all memory.
That description works for pretty much any level of conceptual understanding. It's patterns all the way down. Neat.
I have left reddit for Voat due to years of admin mismanagement and preferential treatment for certain subreddits and users holding certain political and ideological views.
The situation has gotten especially worse since the appointment of Ellen Pao as CEO, culminating in the seemingly unjustified firings of several valuable employees and bans on hundreds of vibrant communities on completely trumped-up charges.
The resignation of Ellen Pao and the appointment of Steve Huffman as CEO, despite initial hopes, has continued the same trend.
As an act of protest, I have chosen to redact all the comments I've ever made on reddit, overwriting them with this message.
If you would like to do the same, install TamperMonkey for Chrome, GreaseMonkey for Firefox, NinjaKit for Safari, Violent Monkey for Opera, or AdGuard for Internet Explorer (in Advanced Mode), then add this GreaseMonkey script.
Finally, click on your username at the top right corner of reddit, click on comments, and click on the new OVERWRITE button at the top of the page. You may need to scroll down to multiple comment pages if you have commented a lot.
After doing all of the above, you are welcome to join me on Voat!
Yep it's called Vedic Math. http://youtu.be/grkWGeqW99c
That's fine, but we're not built to even be able to remember a number that long without some real effort. I couldn't do that in 50 seconds, much less operate on it. I can't even comprehend that part of it.
Dat algorithm.
If this is true, why don't we have processors that calculate based on these same patterns, rather than rote math?
That is to say, you're making the whole thing seem like a simple trick. I'm willing to believe it might be, but if it is, and if it can be this accurate, why are we spending dramatic amounts of energy doing 'real' math if it can all be reduced to 'memorizing a few thousand' patterns?
A superbrain can also help, but I agree with you.
She's bubblesorting in her head
So it's kind of like how people working in factory's can put together really complex things without watching what they're doing?
Similar to how you quickly know the answer to a simple multiplication equation because you memorized all those tables
In fact, there is very little memorization involved. She is one of a few savants in the world. They see math very differently. In some cases, they literally see math. One savant reported that complex number problems formed shapes in his head when he thought about them, and all he had to do was figure out what "shape" matched with the "hole" left in the equation. He never did any calculations whatsoever consciously.
That's really interesting. Consider this, maybe those shapes that savant sees are the patterns I mention in my hypothesis!
its very possible. We have almost no idea what is going on that allows them that kind of subconscious processing capacity.
If you want to check out the documentary I'm drawing this from, it's all on youtube, and it's quite good
One thing that's fascinating is how impressed he is with normal people doing calculations. Like, he's blown away at people who are able to memorize complex calculations, as though they are the abnormal ones.
For example, I can take the fifth root of any number in a few seconds, as long as the answer is an integer between 0 and about 105.
I'm still impressed with the 23rd root thing, and even more impressed at the other thing from the wikipedia article, because multiplication of randomly chosen big numbers is simply hard. Yes, there are patterns, but to know a pattern for every 13 digit number is, in itself, very impressive.
There's definitely a pattern that arises... All the digits in her answer were 1-9 rearranged, and there's only a 1 in 43,046,721 chance of that happening if it was coincidence! Although in honesty, 43 milliion isn't that much in the grand scheme of things really is it?
Well, she has claimed that Goddess Saraswati (Hindu deity of Knowledge) whispered the numbers in her ear, i.e. the numbers just appeared in front of her eyes and she recited them out!
You don't have to memorize thousands of patterns. You just have to memorize a couple thousand numbers and you're set to be able to do this. Most of the digits in the 201 digit number are completely useless. If you gave someone the first 9 digits, they could figure out the answer with 100% accuracy. That means even with the least effective way to brute forcing this task, you only have to memorize a billion numbers. However, you can use tricks to effectively break down the problem into smaller parts. You memorize about a thousand numbers to determine the first 5 digits of the answer. Then you use that to calculate the 6th digit of the answer. Then you memorize about another 1000 numbers to determine the last 3 digits of the answer.
This only requires you to need to look at the first 6 digits and last 3 digits of the 201-digit number. So she doesn't even have to spend time reading the entire number.
She computes trends then? So what you're saying is that she is a Mentat. Awesome.
Kind of like fractions of x/7 but I'm too lazy to explain since nobody will read this
It's survival of the fittest, Max! And we've got the fucking guns!
Not necessarily. There are some people born with the part of the brain that is used when doing a math problem linked to something like the part that is used for breathing. Making it second nature to the person.
Source: I saw a documentary on it and wish someone could find it for me.
You're probably right. I don't think my hypothesis and yours are mutually exclusive though. She probably had an innate ability for understanding numbers, which is what allowed her to recognize and memorize these patterns.
That sounds most accurate.
[deleted]
But does she do the calculation consciously? It might be that some other part of her brain does it for her transparently. For her it might be as effortless as catching a ball.
¯ \ (ツ)/¯
Edit: some sort of formatting made the backslash disappear.
\
Edit: Now you don't have the upper part of your arms.
¯_(ツ)_/¯\
[deleted]
meatwad!
Meatwad make the money, see? Meatwad get the honeys, G.
[deleted]
Ice on my fingers and my toes and I'm a Taurus.
Dance is forbidden.
I count on my fingers
Ahhh.... I thought it was "ice on my fingers and my children are my cars." Not that that made any damn sense.
I am the QUEEEEEN of France!
http://i.imgur.com/avguyBC.gif
My spoon is tooooo big. :D
I am a BANANA!
you just took me straight back to my freshman dorm room
And now, angry ticks fire out of my nipples!
/¯\__/¯\(ツ)¯__/¯\
http://i.imgur.com/e5KLmUc.jpg
http://b1969d.medialib.glogster.com/media/72b7215889d2883b9c6797b41ef0b1afaa3c3639949cdabaa79e1c87ef3b3850/slumber-party-panic-adventure-time-club-29916837-642-362.png
DO THE WAVE!
Check it out I downloaded a little dance
walk like an Egyptian!
Swole.
Guess it's time to switch hands ;)
[removed]
What is this shit?
Ghazi pls leave.
that must hurt...
Kinda looks like a cross between Poopsmith and Homsar
I bet that took longer than 50 seconds.
It's an escape character. It's necessary if you try to do a # at the beginning of the post
¯/¯()\ツ
Now I have "Walk Like an Egyptian" stuck in my head. Thanks.
type ¯\\\_(ツ)_/¯ to produce ¯\_(ツ)_/¯
¯√ (ツ)√¯
¯\(ツ)/¯
¯\_(ツ)_/¯, actually.
Damn it I thought it still looked weird.
= ¯\(ツ)/¯
I know that usually these human calculators are actually just people who memorized massive amounts of multiplications...
But it seems like this lady is legit.
Short of knowing the exact problems ahead of time, 'faking' via rote memorization would be impossible.. There are just too many numbers. Rather, as stated above, these people solve complex problems by memorizing algorithms that would apply to large families of problem types. Easier to memorize 10 rules than 10k different multiplicatons.
yeah, the only way to cheat .. .well
they needed a special fucking computer back in 1977 to work it out to 100% accuracy, so it's not like knowing beforehand would really help the lay person
I wouldn't call someone memorizing massive amounts of multiplication as "not legit". I'd call them "not me".
the brain is highly parallel. I'm guessing it starts with an approximation and narrows things down to exact answer over many iterations taking place at same time
She probably splits it up into more managble, familiar pieces and works from there.
that sounds super easy. we should make that a national standard, and force people to adopt that method.
I agree this method should be more common in the core curriculum of public education.
I think this is just another one of those things people good at math naturally do. Like 23 * 17 might seem hard to do fast in your head but it's really easy if you just do 23 * 10(230) + 7 * 20(140) + 7 * 3(21) = 391
I thought of it as 20^2 - 3^2 . which gave me the answer of 391 in less than a second.
With bigger numbers I always think of it like that, if they are somewhat close to each other.
How did you get the 20^2 and 3^2? I'm genuinely curious the rules involved to derive those numbers as a solution to the equation.
It's calculated by noting this is a difference of squares.
23 * 17 = (20 + 3) * (20 - 3) = 20 * 20 + 3 * 20 - 20 * 3 - 3 * 3 = 20^2 - 3^2
23 and 17 are above and below 20 by 3.
Uh it's just something I noticed sometime in elementary school that I've been using ever since. At first I just noticed that it was 1, 1+3, 1+3+5, 1+3+5+7, etc., away from it. But then I realized those are just squares. I also don't think I knew what squaring something meant, but I knew that you could multiply something by itself.
Edit: Oh! You actually learn this in Algebra 2.
It's the (a+b)(a-b)=a^2 -b^2
Edit: I think it's called the difference of squares formula.
Damn i never thought of that shit. I still don't understand it completely but it's already helping me a little bit. thanks
Damn, that's actually really clever. Now I just have to try to remember this...
are you sure your username is not autism101123?
(math savant)
i did 2320 = 460 then 23 3 - 69 then subtracted 69 from 460
We could call it "collective basis" or something.
Not sure if you're joking or not...but, if you are not joking: why? We have computers to perform rote numerical calculations, and teaching kids to think algorithmically (which would be the only way to go about solving something like this in your head) is impressive...but unless we have to engage in a Butlerian Jihad and the Orange Catholic Bible prohibits the use of Thinking Machines...it's not of much practical use except as a parlor trick.
We're far better off with what Common Core is trying to teach: fundamental concepts of math and a basic sense of how numbers and mathematical operations actually work. This leads to an understanding of math instead of what we have often had in the past: rote, mechanical, algorithmic learning of how to do a math problem without understanding why. That might work okay for arithmetic, but it kills kids' desire to learn math once they get up to algebra and have to start thinking more abstractly.
As far as breaking a bigger problem up into smaller problems...I feel like we already do teach that. I mean, we taught that even when I went through elementary school about two decades ago.
Side note: OH DEAR GOD. THE early 90s were 20 years ago.
I think your post is well written, but I noticed a wee little error. I believe you meant "rote" as in mechanical repetition, not "wrote" as in scribbling symbols on paper.
I like the idea of getting kids to understand why the math works instead of saying do it just because this is how it is done, but algorithms are pretty important too. They seem to be taught in any computer science course I've ever taken and I think they have their place. Plus, once you understand the math, it is really nice to have a simple, algorithmic way to simplify a problem, such as the chain rule in calculus.
I'm not saying that we shouldn't show kids specific methods for doing things and teach them various standard tools for working out solutions. I'm talking about what I'd broadly call algorithmic learning/teaching.
For example, when I was in elementary school we learned a form of subtraction called "compensation" (sometimes referred to a "sliding board subtraction"; it wasn't this, either; that makes sense, number theory-wise). It was a horrible, nonsensical way to teach subtraction, because, while it gave the right answer, it gave no tangible, graspable reasoning behind why you were manipulating the numbers in that way.
That's just one example, but that's how a lot of math has been taught over the years:
Do this. Then do this. Then do this. Then do this. Then there is an answer.And that doesn't work once you get up to even just solving things like basic algebraic equations, because you have to be able to understand the why and how in order to think through the problem.Also: I know wrote vs. rote. Just a typo. Thanks for catching it. If I bothered to reread stuff I post on here, I'd probably have caught it. But, then I'd also have been spending time proofreading my reddit posts. And that's a sad road down which I do not yet want to travel. (Not saying that it's sad you noticed. I probably would have in someone else's post, too.)
The mid 90s were 20 years ago.
It's DJ Jazzy Jeff's 50th birthday today!
The spice is life baby...
I hear that it must flow.
Until the end of time.
Do you have kids? Just curious.
No. But I work in a K-12 school system as an IT admin (and have worked in K-12 education for about a decade, now), so I have constant contact (and am friends) with plenty of teachers and students. My mom taught high school math for 35 years (just retired, but still volunteers as a tutor, and is familiar with the common core standards); my dad taught elementary school for 33 years (retired a few years); and my aunt (who I'm close with) has taught third grade for about 34 years and is still teaching.
So I get a fairly broad perspective on education. I've heard an especially large amount on what upper-level math teachers have found deficient about elementary-level math education.
I also have young quasi-nephews and nieces who I often spend time with. So kids aren't a completely foreign species to me on a personal, non-professional level, either.
[deleted]
My (significantly younger) brother just "suffered" through the high school curriculum for that past two years (when the state's full adoption kicked in). Or, wait, not "suffered", but did just fine and had no issues.
And, frankly, my mind's not fixed on this at all. If someone were to come to me (once we have a go at actual implementation, not one or two years in) and present evidence that the standards weren't working or that there is a better set of standards which would work better, I'd be all on board with the alternative.
Because Common Core isn't something created out of whole cloth. They're evidence-based, using research on what techniques and topics are most useful to most students. They were built collaboratively between teachers, administrators, and educational experts based on what worked in existing standards, and this was done at the prompting of the Council of Chief State School Officers and that National Governor's Association, so they're not even something that was just taken up by the federal government of its own accord. They're also intended to build on the subject matter each year to a cumulative whole, so something that seems pointless one year will almost certainly turn out to be prepping for a new concept the next year.
In fact, speaking of evidence, the earliest results we have would seem to indicate that the Common Core standards are having the desired result.
Have you read the math standards? Because they're nothing terribly outrageous or strange. They're also not wildly, wildly different from what we had before, just more focused on conceptual learning and more deeply focused on fewer topics. You can even see how each year builds on previous years and see the whole structure.
They're a basic framework adopted (more or less) nationwide to try to address former deficiencies in the standards and ensure that all our kids are all getting roughly the same math and reading content regardless of what state they're in. It's about time we joined every other developed nation in having some basic national standards. And as standards go, they're not terribly restrictive: local schools still set the actual curriculum; the standards just define the material that students should be proficient at in most grade levels.
If a student is having trouble, their parent should set up a meeting with teachers and/or principals for remedial work or tutoring, so I hope you do that if you have not already. Most schools and most teachers will work to help a struggling student. I know my mother would stay after work until 4:30 or 5 pm most nights (hours after she was required to be there, contractually) to work with students who were struggling with material if the students were willing to put in the time and effort. Heck, she does it voluntarily, now in her retirement, because she enjoys helping students.
I believe most of the problems we have with education in our society are from lack of parental involvement anyways. Additionally, I don't believe the ends justifies the means and just because kids may be performing better on tests does not justify the methods used to get them there. This is a fundamental issue with CC - at least in my opinion. To me, CC is all about political gain and economic profit (as most things are these days) . There is very little altruistic about it. But that's just my opinion and I don't really feel like a 7 paragraph justification at this time (although am fully prepared for one). I do appreciate your thoughtful commentary though. It's always good to hear all sides. Best, me
spelling edit
[deleted]
Awh, fuck. I know that. I should edit my copy better. Thanks for catching it.
It's almost as if people thought of teaching methods that simplify calculations before... Like logs for example, which are taught in absolutely every maths class ever. However, since we now have calculators, nobody is interested in remembering log tables anymore (and for good reason).
It's called Vedic maths. My school made it compulsory for a year. Many kids failed in it and eventually it was made an optional subject. But Vedic maths made regular maths easy.
Edit: I studied in India
Sadly, with no child left behind, I'm pretty sure would be low on the list.
I don't think they were starting a pun thread.
I didn't mean to make a pun. Wait - I made a pun? Was it /r/DadJokes level?
They were making a pun thread, that's what common core math teaches
And that's what confuses and scares us old folks...
"What do you mean, you don't know how to do long division? How do you divide 1302 by 25?"
"You take 25x10 (250), and subtract it from 1302. Repeat, counting how many times you do that (5 times). Then go to 25's and and keep on subtracting those until you get close (2 times), add up the number of 25s and that's the answer with remainder... 52 remainder 2
Its a great method if you're already inclined to think that way, I'm not sure how easy it is to teach though
Easier than long division.
And thats why I'm in engineering. I miss the jokes more often than not.
I don't understand what you mean
Exactly!
If we were actually preparing people who would calculate the roots of 200-digit numbers on a regular basis, teaching them this heuristic is a fantastic idea. Sure their parents won't be able to help them with their homework, but their parents don't even remember how to do long division.
That's what I do. I'm not super good at it, so imagine it on a larger scale, but if instead of trying to multiple 8 * 15, think about 15 * 2 = 30. So in my head it goes something like
[[15,15] (30), [15,15] (30)] (60) * 2 = 120.
I think of the numbers in chunks that are easier on a small scale and put them together and the math comes almost immediately.
But like I said, I'm not very good at it.
that's exactly how i do my math, but what i was referring to was the common core mess that the US pushed on the teachers and children. not everyone does things like us, but they're grading them on doing it one specific way.
I was agreeing with you. They should be teaching more advanced processes like this once you reach high school.
got it. my fault!
What's the point of it?
It's very useful. It started for me in elementary, I'm not good at memorizing and we were supposed to know our "times tables." I just got good at counting really fast. So for something like 8*7, 5th grade me would have thought, "7, 14, 28, 56."
nazi
Ya but how much do you have to split it down to make it manageable? I'd lose track after breaking it down into more than a few calculations. That's what's so insane.
I would say the same thing about rubics cubes before I learned how to do them. After I learned the 3x3x3 and played with it enough times that I could start to create my own algorithms I realized that much of my knowledge applied to 4x4x4 and 5x5x5 and 6x6x6 and 7x7x7. I was able to almost completely solve a 4x4x4 the first time I sat down with one. The thing is that when you work with something enough you get a few small patterns to look for then when you find them you already know the answer to that whole section where the pattern applies. To give you some idea what that is like with numbers, a 3x3x3 has over 12,000,000,000,000 possibilities so each state can be thought of to represent a number. So it isn't unheard of to do very large calculations with only a couple of small algorithms.
She is insanely brilliant saying all that though and probably sees numbers in very different ways.
Yeah, still insane, but it's kind of like if you asked me 43 * 27. I would do 4 * 27 = 108. 108 * 10 = 1080. 1080 + 27 * 3 = 1,161. She just does it on a whole different level.
"Tell how to make 10 when giving the 23rd root of 916748676920039158098660927585380162483106.........."
You thought it was Divide and Conquer, but it was me, Dynamic Programming!
Edit: Dionamic
She probably sits next to an Asian kid at all times.
She is Asian ...
Have an upvote for remembering that India is indeed part of Asia. And for also knowing what a continent is.
India is a subcontinent!
Speak English, Doc! We ain't scientists!
This was a particularly bad case of somebody being cut in half.
The wrong kid died!
Wrong Kid Died
Get outa here dewi. We're doin cocaine! It turns all your bad feelings into good feelings. Its a nightmare!
And you didn't pay for drugs, not once
And you slept with me too, and I've had confused feelings about that for a long time!
and you didn't once pay for drugs
It gives you a boner.
In twenty years, not once have you thrown a woman my way. You don't think we like cheating on our wives too?
"The siamese cat is a symbol of nobility in Ancient Egypt."
"Fuck nobility!"
"Fuck Ancient Egypt!"
Fuck... cats!!!
Are you kidding me?!?! A Walk Hard references thread! EVERYBODY GETS UPVOTES!
bouncing on trampoline -"It has changed me!!, I'm inventing this whole different type of music called shmusic.!!"
i dont understand the reference
He needs more blankets and less blabkets!
"I'm cut in half pretty bad here, Dewey."
[deleted]
It's what plants crave.
Think of it this way. If someone is asking me what 8×112 is, my first rough estimate would be "800ish." I did that by calculating 8×100. While I am saying that I am fine tuning, so now I either know 8×12 is 96 or I go through another iteration "It's about 880" (8×100 + 8×10). Then I would finally say 896 on the third pass after I added 8×100+8×10+8×2.
So you are going through the process iteratively fine tuning the answer as you go.
That is a much easier problem that could be solved in 50 seconds.
Right of course, the person I was replying to implied that they didn't understand what an iterative process would be. I have no idea how to solve the posted problem, but was providing a simple example of an iterative process that almost anyone could understand.
Damnit man I'm a doctor not a scientist
You're paid to think, mister sciennntist. https://www.youtube.com/watch?v=Q2FJf6opsoY
My ass. Humans cant even focus on more than one thing at once much less conscious parallel processing.
Nobody said "conscious."
You're talking about doing a mathematical calculation. You arent exactly blurting out calculus in your sleep.
The brain actually does a lot of parallel processing, but if she's a mental calculator its probably highly likely that she does most of it subconsciously :)
edit: Sub instead of un*
Does anyone else read an emoticon at the end of a reddit post as "so, fuck you, buddy!"?
[deleted]
^^^^^^^^^^^^^^^^0.3817
Oh, I get it, now!
...so, fuck you, buddy!
I always do it when people seem aggrevated, it usually shows in the reply whether they were/are or if they just speak like that! :P
Nah, come on. You do it to be a prick.
But do you know why you do things just to be a prick?
Because you're a prick.
;-)
How?
I'm sure he means "subconsciously."
Gonna steal something from The Name of the Wind by Patrick Rothfuss. I'm sure he got it from somewhere else.
I throw a ball into the air, underhand, at an angle of 45 degrees at an approximate velocity of 20 mph. Accounting for wind speed and all other environmental factors you can imagine, calculate the exact location of the ball relative to me when it's 4.5 feet from the ground in its parabolic arc, and tell me exactly how long it will take to get to that position. I'll go negotiate an auto loan while you do the calculations necessary
Instead, why don't I just throw a ball at you and you'll catch it?
That's how your brain does complex math subconsciously.
Thanks thats exactly what I meant, also your example is pretty darn accurate!
You do a lot of conscious actions with unconscious step-by-steps to do the action. You don't concentrate on leaning forward, lifting up your leg and bending your knee just enough to have your foot land flat so that you fall on that leg that's going to balance you before you do it all over again.
You just walk.
Yes, but this is a conscious thought process we're talking about.
This Indian lady begs to differ.
She is either the exception, does really fast serial processing using her method or just has a really good method.
I should think it's pretty obvious that she's an exception
Exactly, which is why saying the human brain is highly parallel is not relevant
Maybe not consciously the way you're thinking about it, but the brain IS highly parallel. It's why we're still better at visual and voice recognition than machines.
We literally can walk and chew gum at the same time.
I specified that Im talking about conscious parallelism.
My bad!
We literally can walk, keep balance while walking, avoid hitting objects nearly flawless while walking, asert any danger during that walking, compensate for elevations near effortless while walking, constant keep track of a dozen objects unconciously and chew bubble gum at the same time, while also thinking about whatever with accompanying audiovisual imagination that probably grabs memory in raw data at a higher bandwidth than the average RAM stick, all at the same time.
I struggle to take a poo and reddit at the same time.
Choose the poo.
Pooing ain't easy but it's necessary
That's how I choose which kind of cheese I want.. Gouda or chipotle Gouda
But... narrowing down can't be done in parallel...
it can, considering that each iteration involves a random factor. Several parallel processes can compute new iteration with a different random factor, then pick the one that's closest to the answer,
Yes, you can get the answer with brute force and do many calculations in parallel. How one would figure out which one of those is the correct answer afterwards is not trivial, may be very complicated and can not be done in parallel.
Regardless, my point was that you can't iterate or narrow down in parallel, where, over many steps, you take the previous answer to calculate a better results. There is no previous answer in a parallel computation.
Hope that makes it a bit more clear.
Its not highly parallel at the conscious level. Try multiplying 13x7 while simultaneously composing a haicu about a dog.
yes, not on conscious level. I'm pretty sure when people like her are calculating math problems, they don't do it the same way we do it - using conscious thought all the way thru. Her consciousness probably just starts the process, and then the answer sort of comes up by itself from the subconscious level.
The real question is, how was she able to do this so quickly and easily when no one else can? What is it about her brain that was so special?
Like Newton's Method possibly?
I thought our brain is single threaded, but very good at pretending to be parallel.
A place to start would be to look at the total length of the final number, 201 digits. 100,000,000^23 would be 184 digits long. 1,000,000,000^23 would be 207 digits long. Therefor the value must lie somewhere between those numbers. IF you start out with an approximation of 4.8677e200 I was able to simplify it down to 3.2e823sqrt(3.248677)
Took me a little longer than 50 seconds though
You're 1 off on the digit counts. Should be 185 and 208, respectively.
~~(10^8 )^23 = 10^8*23 =10^160+24 =10^184~~
~~(10^9 )^23 = 10^9*23 =10^180+27 =10^207~~
Edit: Nevermind, i forgot the first digit
Yes, but the exponent just shows the number of zeros. It doesn't include the 1. Example: 10^3 has 4 digits.
Take your fancy talk and git outta here. We's talkin math, not sum kind o new fandangled language.
That's smart
BUt did you do it in your head?
[deleted]
How do you use Fermat's Little Theorem for non-integers?
Carefully. Very carefully.
There's another "human calculator" in the US. They found out he uses the portion of his brain normally used for reflexes and motor control to do math calculations.
This is the man you're talking about: http://thehumancalculator.com/video/ He was on Stan Lee's Superhumans when they did a brain scan while he did math and figured that out. Pretty neat stuff!
does he still have reflexes
Through 4chan.
"In 2015, at /r/atheism, she was asked to give the 23rd root of a 201-digit Mountain Dew promotional code; she answered in 50 seconds. Her answer -- 546,372,891 -- was confirmed by calculations done at the US Bureau of Standards by the UNIVAC 1101 computer, for which a special fedora had to be worn to perform such a large calculation.[14]"
m'institute
It is by will alone I set my mind in motion. It is by the juice of sapho that thoughts acquire speed, the lips acquire stains, the stains become a warning. It is by will alone I set my mind in motion.
Using log tables I reckon.
[deleted]
The given number doesn't end in a zero. Note that you have to scroll right to see the whole thing.
Seriously http://imgur.com/fSqYcEf
the human brain is a computer running on an outdated OS? I'm sure if we figured the brain out you could download Smart 2.0.
Because there are rules in multiplication and division. For example, multiples of 5 can only end in 0 or 5. Multiples of 2 can never end in an odd number. Numbers that are multiples of 3, must have all their singular digits add up to a multiple of 3. A number is divisible by 4 if the last two digits are "00" or if the last two numbers are a multiple of 4 when not added together. There are a lot of rules for this. She probably mastered them all.
She started looking for multiplication patterns in the last sets of digits to the far right and started removing root-numbers that would not fit the pattern.
Autistic savant?
There was a British documentary about someone who is a mental calculator. For what its worth, I believe that they found that the part of his brain that he uses to do the calculations is linked to the vision center, a part of your brain that is constantly processing lots of information very rapidly.
Mentat
Vedic Maths FTW! http://en.wikipedia.org/wiki/Vedic_mathematics
Modular arithmetic, more specifically modular exponentiation. She was not trying to find the root of the entire number, just trying to find the root of the last part of it.
The first few digits of a number do not affect the last few digits of the answer when you raise it to a power. For example, 871 ^ 2 = 758641, 9871 ^ 2 = 97436641, 99871 = 9974216641, and 19871 ^ 2 = 394856641. Notice that they all end with 641 and the last three all end with 6641. Adding or changing digits on the front will never change the last digits. The formal version of this relationship is derived and explained on the Wikipedia page on modular exponentiation.
The number above ends in a 1. That means that its 21st root must end in a 1, 3, 7, or 9 because only the last digit of a number affects the last digit of the answer under exponentiation and 1, 3, 7, and 9 are the only numbers which can yield an answer ending with a 1 under exponentiation. There are a large number of similar tricks
The other people are also right. She probably memorized huge tables of multiplication and powers. She's also probably very fast with calculations in general and must be very careful to not make mistakes. She's good. However, the interesting thing here is the mathematics that would allow anyone to do this same calculation, not any special skill she has. It would take you an afternoon or two to learn this technique and, while you couldn't find the root in your head in fifty seconds, you could find it on paper in ten minutes.
Knowing the tricks takes this performance from superhuman to merely very impressive.
I assume first that it is an integer, then I'd do pattern analyzing. For a simple case, try finding the fourth root of a smaller number like 152,587,890,625. That is still a massive number, but I can break it down.
First, it has 12 digits. To be the fourth root, our answer is probably between 100 and 1000 (100^4 = 9 digits, 1000^4 = 13 digits).
Next, we look at the first three digits on the right. 625. We know for a fact that the number we are looking for ends with a five, so the format we are looking for is XX5.
Furthermore, we can tell it is likely a power of five, give that 0,625 is a very frequent chain in powers of five (25 happens all the time, 125 and 625 alternate, then the next digit goes 3/5/8/0).
Given that we think it is a power of five between 100 and 999, it is either 125 or 625. However, it is somewhat simple to show that 125 is not large enough, as 100^4 is not large enough (100,000,000). Therefore a reasonable guess would be 625, confirmed by calculating it out.
I'd use a similar process on that question. First, find the approximate range of the number you are looking for then look for common patterns. It is still an extraordinary achievement, but that is likely how it was done. Without looking at the answer myself, I'd guess it is a factor of 3 roughly around 400-600 million. Maybe something like 3^2 or 3^3 times a large prime.
What's extraordinary is that this was done quickly and correctly, a feat that likely required knowing 1000s of patterns and quickly using mental math to narrow down guesses. Even if you knew the exact process she used to reach her conclusion, it is virtually impossible to duplicate that speed.
In ancient times, aliens set up outposts on the subcontinent; they waged wars, and probably interbred with the humans who lived there; some of their genes pop up from time to time.... ;)
Well, a rough estimate could be done in seconds fairly easily. Powers of 10 tell you the numbers of zeros after the 1, i.e., 10^1 = 10 (2 digits), 10^2 = 100 (3 digits), etc. So to get 201 digits you'd want 10^201. That is the minimum 201 digit, of course. Noting it starts with a 9 means it's going to be just shy of 10^202.
Now you want 23 factors, so you need to split 202 into 23 values, i.e., 202 = 23x. If you can't do division quickly, you can notice that if x = 10, then you'd have 230, so x is slightly less than 10. If x = 9 you'd be one less 23 from 230, meaning 207. At x = 8 you'd be another 23 lower at 184, so you know it's going to be slightly less than 8.
So your current estimate is slightly less than 10^8, but well above 10^7, meaning it will be of the form y * 10^7, where y^23 must be less than 10^18 since:
[y * 10^7 ] * [y * 10^7 ] * [y * 10^7 ] ... (23 times) = y^23 * 10^7*23 = y^23 * 10^184
Which is 10^18 shy of 10^202 and must be mad up by y^23. Doubling is generally easy as I already know 2^24 = 16.7 million from 24-bit colour, so 2^23 is half that, about 8.3 million, which is almost 10^7 and I need closer to 10^18. So 2 < y < 10. If we guess y = 4, 4^23 = 2^23 * 2^23 is about 8.3 million * 8.3 million, which is slightly less than 10 million * 10 millon, which is 10^7 * 10^7 = 10^14, which is still 10^4 shy of 10^18 we're trying to achieve. So 4 < y < 10. Double again, y = 8, 8^23 = 2^23 * 2^23 * 2^23, which is slightly less than 10^7 * 10^7 * 10^7 = 10^21. Now we've overshot by 10^3. So 4 < y < 8.
Given that 4 gives us 4 magnitudes too low and 8 give 3 magnitudes too high, and this is with aiming a little high (10^202 which is slightly higher than the number given to factor), I'd guess it somewhat below halfway between (due to the exponential rather than linear growth), so less than 6 (halfway between 4 and 8), so I'd start with y = 5.
Now my guess for the solution is 5 * 10^7.
Although I wrote all of the above out, I did it in my head in about 30 seconds. Now to do better than that, I don't see many shortcuts left, so I'm afraid it'd probably be minutes to get even an approximation of the next significant digit. Recognizing that the number will be in the tens of millions (8 digits), it would take a very long time to get more than the first few digits, and keeping track would get very difficult after this.
I'm amazed at her ability, but I can see at least how to get an engineering estimate quickly. (I'm an engineer so this is a useful skill for order of magnitude estimates.) I'd love to find out how she did the rest, unless it is one of these "I don't know" savant things where even she doesn't know.
She's the Asian Carol Vorderman
Lucky guess?
I saw a program once about a similar human-calculator-guy. They did a scan of his brain while performing ridiculously long multiplication problems, and they found that his brain was actually processing the information in the portion of the brain that is typically used for unconscious, reflexive eye movements. I'm not an expert in neuroscience or mathematics, but that really made a lot of sense to me. Obviously certain types of computations have to be calculated by the brain at lightning-fast rates to prevent too much latency in our sensory experience, and certainly processing the vast amounts of visual data in 3d space fits the bill.
It's super incomprehensible for normally-wired people, because the experience would be so deliberate and arduous using the normal processing centers of the brain. It is easier to imagine when you realize the immense amount of data your non-genius brain is already capable of processing at lightning fast rates with literally no effort.
If you compound that innate ability with training, as described in coinclink's post, it seems downright feasible--but super inspiring!
She...slap
She was recently confirmed of being a cylon
Her strategy was to simply put a dollar $ sign in front of the numbers. The rest just falls into place.
Source: I know some Indians.
The juice of sapho.
Really gives you a little glimpse at the true power of the human brain. I hope some time in the near future we will be able to unlock the true potential of our brains.
If you just calculate 10 ^ (201/23) you already get pretty close. The rest is "just" fine tuning by rules others already posted.
Magnets
She's a Vulcan.
It's not technology, it's Magic^TM.
Search for a TED talk by Arthur Benjamin. Towards the end, he multiplies two large numbers in his head and thinks out loud. That'll give you a sense of how they calculate these things.
I know how: it didn't happen.
Just to answer your question, Vedic Mathematics. You can numerous formula to do such calculation.
It's incomprehensible o_O
Impossibru even.
Incomprehensibru.
dude..
Something something Indian and accountant joke.
It's ok, I'm Indian.
In situations like this I am more likely to suspect fraud than brilliance. It isn't that I am a pessimist, it is just probability. They also said Jesus rose from the dead, and that some 4 year old girl gave birth. These things might be true, but again, i'll choose the probable answer until proven definitively otherwise.
You believe only one person out of 7 billion solving this math problem in their head, is not a small probability? The world isn't going to cave to your personal needs for proof and come mail you a letter for everything you want proved. If you did not read the article then that is your own fault.
Where did your logic even come from?
I don't think you really understand probability, or how numbers work. Specifically I don't think you appreciate how difficult this problem is. More importantly she apparently solved the problem in about the time it would take a normal person to remember all of the digits of the solution if they had known it before. It is more likely she knew the problem before hand than she is a human gifted with one in a universe, nay multiverse, set of math skills.
Math is a lot simpler than what you think it is, honey.
Do some research for yourself for once
Here is some more
Educate yourself.
The article clearly states that a team of people had to create a program to be able to solve the problem. If you think that she ALONE did that, instead of simply solving the problem, then you are fucking stupid.
Well, you don't get called Mental Calculator just because it sounds cool.
Also, Indian parents.
She uses an intel i8 quad core, thats how!
The problem is actually much simpler than it appears at first glance if you memorise a logarithmic table, which was not unheard of in the days before electronic calculators.
You are trying to find x^(1/23)
Take log, and you get log(x^(1/23)) = (1/23) * log(x), using log(a^(b)) = b * log(a)
Let's say your number is 55745.... followed by 196 more numbers.
Since log(a * b) = log(a) + log(b),
you have log(5.5745 * 10^(200)) = log(5.5745) + log(10^(200)) = 0.7462 + 200 = 200.7462
So now all you have to compute is
(1/23) * (0.7462 + 200) = 0.043478 * 200.7462 = 8.728
Note that the above line contains all the calculations involved. The rest is just manipulation and looking up the table.
Apply the inverse log, and you get 10^8.728 = 10^8 * 10^0.728
The first part is simple, the second part you can look up in a table.
EDIT: A brief history of log tables
Log tables were essentially the calculators of the past since they simplified complex calculations.
A general rule of calculations is that addition and subtraction is simple, multiplication and division more difficult, and exponentiation (raising to a power) more difficult still.
The "power" of log tables was that it reduced exponentiaton to multiplication and multiplication to addition.
So let's say I was an engineer from 1900, and I wanted to calculate 6.33545 * 7.434324.
I would look up a log table to get log(6.33545) = 0.802 and log(7.434324) = 0.871. Add them together to get 1.673.
Next, look up an inverse log table to get 10^0.673 = 4.71. Finally multiply by 10 to get the final answer.
If I had gotten 2.673 instead, I would still look up 0.673 in the table but then multiply by 100.
Notice that in the above example, I got around doing multiplication by looking up some numbers in a table and then doing some addition. Similarly, with a log table, you can get around doing exponentiation by doing multiplication.
So obviously log tables were very useful before the age of computers, and some people simply committed it to memory to save the trouble of having to look up the numbers everytime. Hans Bethe is a notable example.
I glossed over some details but you can find a good step-by-step explanation of how to use a log table here.
I attempted to use this method (obviously using calculators), but there are a couple of problems with it. Using 4 decimals gave me a 23rd root of approximately 546 372 666, which is 225 away from the correct answer, 546 372 891. Since you're effectively looking for 9 significant digits, using 9 significant digits in the original should be enough, and indeed this turns out the answer. Your method does reduce the problem to calculating three things:
I still don't see how it's possible to do these calculations in your head. I mean rough approximations get you fairly close to the answer, but it's not really enough. To keep the error margin low enough that you can round the final result to an integer, you need to do estimations with 9 significant digits all the way through.
yea, even simplifying it to this method, who can do this in 50 seconds in their head...? lol
Shakuntala Devi
Technically no one. She died a couple of years back.
R.I.P.
Math. Not even once.
This is why I dont do maths. I failed in maths and see I am still alive.
There are other people like her that can do these calculations
Who? This is extremely rare. I think Kim Peek could do these kinds of things, he's dead now as well.
Daniel Tammet and Scott Flansburg for instance
No, there are others.
TIL of Shakuna Matata, a mental grill computer, when they asked her what 210 + 210 was, the answer was so dank that her head exploded and she became Neil DeGrasse Tyson.
/r/circlejerk
LMFAO
It's like he wasn't even paying attention
xD your comment was way more awesome than that which got 2 golds up there...
Well, not anymore...
That Shakuntala Devi's name? Albert Einstien.
Albert Einstein was bad at math...
Oh, right.
I read somewhere that she was like a mental calculator!
Shak Deisel
Dude.... just .... Okaaay?
Rub it in.
LOL made me spit out of my coffee.
Who's that? Sounds familiar.
Sounds like a fantasy league trophy name
Hahahahahahahahaha
Bless you.
Willem Klein, I guess. He calculated the 73rd root of a 500-digit number in 2 minutes and 43 seconds. He used to work as a computer at CERN.
The guy who made it out of Cube alive.
Huh?
It likely isn't the way it is done. Knowing the last digit of N, you can eliminate certain choices of the last digit of n as your root. I.E. if the last number of N is a 5 then n ends in 5. If the last digit of N is 1, then the last digit of n is either 1,3,7, or 9. It comes down to memorizing a bunch of cyclic groups and then computing how they work together.
It's not memorizing cyclic groups. 23rd powers actually have a 1 to 1 correspondence between the last digit and the last digit of the answer.
What you're basically saying is that 7 to any power has to end in 7, 9, 3, or 1. However, we know that we're using 23rd powers. So we know that 7 to the 23rd will always end in a 3 because 3 is the 23rd number in that cycle. It just happens to work out that for each of the 10 possible digits the number can end in, you get a different digit in your answer.
So that's 1 less digit you have to memorize. You can cut it down much further with other tricks. You don't have to memorize the first 8 digits either. You can always trivially calculate/estimate the 8th digit using the first 7, ad how close the given number is to the number you memorized.
I posted a solution in response to some other comment, but in realty you only have to memorize about 1000-2000 numbers to be able to do this in under a minute.
http://imgur.com/1zef6zN
To obtain the last digits, if you know that the answer is an integer, it is not that hard (it is way easier to find the root, than to compute the 201 digits number from the root): it ends by a 1, so the root is odd. A quick check tell us that 3^23 ends up with a 7, 5^23 by a 5 and 9^23 by a 9, so the only possible last digit is 1. From there, the last two digits of (a1)^23 are congruent to 23 * 10a+1, so a is such that 3a is congruent to 7 mod 10, ie a=9. By doing that repeatedly, you can obtain the answer quite quickly.
"quick check".
"quite quickly".
This is like when a professor is writing a proof, jumps 12 steps while saying "it follows that..."
The intermediate steps are left as an exercise for the reader.
I felt everything was easily and precisely explained. Of course 50 seconds is insane, but did they really need to write a special program to solve this? Also, are you people just trying to be funny by saying you don't think this was done in an easy to follow manner?
The thing is that most of the answers is multistep solutions combining logarithmic tables and several approximations that takes for the average person to read and understand. Quickly identifying the correct tools and being to use them on the fly is making you a good mathematician. Being able to do so without any calculator, pen or paper is somewhat impressive. Being able to do so in a Quick efficient manner is very impressive, doing it with multiple methods for absurdly huge numbers that many common calculators can't exist you with is almost insane.
ones digit of multiples of:
9's -> 9 1 9 1 9 1 ... 23rd element is 9
7's -> 7 9 3 1 7 9 3 1 ... 23rd element is 3
5's -> 5 5 5 5 ... 23rd element is 5
3's -> 3 9 7 1 3 9 7 1 ... 23rd element is 7
1's -> 1 1 1 1 ... 23rd element is 1
Makes sense now. They specifically chose 23rd root because it makes the question easier than other numbers that sound equally difficult to a laymen
It's actually very easy. the powers of 3 cycle in 3,9,7 and 1. take 23 mod 4 and you get it. the powers of 5 always end in 5. the powers of 9 end in 9 and 1 so you just take 23 mod 2.
That picture about drawing an owl.jpg
Most people don't know that much about math because they don't need to. Even your simple answers are like wizard level shit. I appreciate it though, thanks.
Yup. The last digit can't be even, because the product ends in "1". It can't be 5, because all powers of something ending in 5 end in 5.
It might be 1, because all powers of something ending in 1 end in 1.
Stuff ending in 3 goes 3-9-7-1 in that sequence. Something ending in 3 raised to the power 23 would therefore end in 7. So the root can't end in 3.
Similarly, 7 goes 7-9-3-1, so the root can't end in 7 for the same reason.
And 9 goes 9-1, so the root can't end in 9.
So it has to end in 1.
These sequences are things which can be worked out mentally in seconds, even assuming they weren't pre-known to someone who was likely to be asked a question like this.
So yes, a quick check.
Yes, there's a reason why the question is a 23rd root; it makes it a lot easier (strangely enough)!
That trick only works for certain roots; it works for 23 rd roots; other roots blurs the digits together; for example anything ending in 1 squared ends in 1, but so also does anything ending in 9. 23rd roots have property that all the 23rd powers give unique digits so you can work it from the right.
Wait, so she got to pick the radix?
There's certain stereotypical questions you give fast calculators. You want them to be actually able to do it in a reasonable time. Also if you're pitting one calculator against another you want to find the one that can do the biggest numbers the quickest; it will be a much more spectacular contest if you use certain roots.
Indeed, knowing that the answer is an integer is a big help.
A integral root of an integer is either an integer or irrational -- and we have no better way to express irrationals than "the twenty-third root of..."
Quizzes and puzzles never ask you a question if you cannot give an answer. If the possible answers are "3" or "it cannot be answered", it's 3.
The answer could obviously also be asked to a given number of significant figures in the case of an irrational.
You can even find all the last digits directly, by using the same principle as RSA.
Since 23 x 87 = 1 (mod 100), just raising the last 3 digits to the power 87 will give you the last 3 digits of the number.
In Python:
So it's easy to find the correct solution from rabbitlion's approximation! You can compute an 87th power in just a dozen multiplications by using binary exponentiation.
Took me a bit to understand the last part, so a step-by-step for those who might be confused:
Since the 201-digit number ends in a 1, we know that the 23rd root of the 201-digit number ends in 1, from the property of 23rd powers. The key to finding a, the second-to-last digit of the answer, is that:
(a1)^2 = a1 * a1 = (10 * a + 1) * (10 * a + 1) = 100 * a^2 + 2 * 10 * a + 1^2.
So to find the last two digits of (a1)^(2), we can throw away the 100 * a^2 term and see that it is the same as the last two digits of 2 * 10 * a + 1^2, or 2 * 10 * a + 1.
So to find the last two digits of (a1)^(x), where x is any positive integer above 2, note that
(a1)^x = (10 * a + 1)^x = ... higher order terms like 1000 * blabla + 100 * blabla + x * 10 * a * 1^(x-1) + 1^x.
and we can similarly throw away the 100 * blabla term and higher terms and see that it is the same as the last two digits of x * 10 * a + 1.
Just in case the above part is still be confusing, here's the whole thing (binomial theorem/expansion):
(a1)^x = (10 * a + 1)^x =
(10 * a)^x * 1^0 + (x choose 1) * (10 * a)^(x-1) * 1^1 + (x choose 2) * (10 * a)^(x-2) * 1^2 + ... + (x choose x-2) * (10 * a)^2 * 1^(x-2) + (x choose x-1) * (10 * a)^1 * 1^(x-1) + (x choose x) * (10 * a)^0 * 1^x =
higher order terms + 100 * blabla + x * 10 * a * 1^(x-1) + 1^x.
So now we know that the last two digits of (a1)^23 are the same as the last two digits of 23 * 10 * a + 1. Which is the same as saying that (a1)^23 mod 100 = (23 * 10 * a + 1) mod 100. We already know that the last digit of each is 1. We can go ahead and calculate that (23 * 10 * a + 1) mod 100 = (3 * 10 * a + 1) mod 100 since 20 * 10 * a > 100.
So then we have something like (plugging in 1, 2, 3, 4 for a):
(3 * 10 * 1 + 1) mod 100 = 31
(3 * 10 * 2 + 1) mod 100 = 61
(3 * 10 * 3 + 1) mod 100 = 91
(3 * 10 * 4 + 1) mod 100 = 21
etc.
We need something that gives us:
(3 * 10 * a + 1) mod 100 = 71, since that's what the last two digits of the 201-digit number are, and the only thing that gives us that is a = 9.
I haven't done the math beyond this to get the third-to-last digit, and I wonder if it isn't so easy anymore with this method. This method is made greatly easy by the fact that we're given a 1 for the last digit. If we have 2, we have this instead:
(a2)^23 = (10 * a + 2)^23 =
higher order terms + 100 * blabla + 23 * 10 * a * 2^(22) + 2^23.
Not as pretty. Similarly, let's keep the last digit as 1, say we've found that the second-to-last digit is 9, and we're trying to find the third digit. What can we say about 91^(23)? Hmm, I don't know. Or about (1000 * b + 91)^(23)?
I wonder if at some point in this process (of correcting for the approximation that's inherent in the log table memorization method), you have to go to the "plug in and check" method described here. I almost wonder if that "plug in and check" method may actually be better to rely on in general. This method breaks down/gets more cumbersome pretty quickly when the last digit doesn't turn out to be 1, in terms of the number of little calculations you have to do.
Yep.
I will provide you with a 201 digit number and you can demonstrate doing this quite quickly perhaps?
With u/al_jebr below, yes I could probably (let say find the last 5 digits, which with u/sc2math's technique above would give the complete number). With my own technique, it would be a bit boring to do 5 digits. Edit: obviously not in 50s, but I believe I could do it in a few minutes.
If that is the case that is fantastic. I don't think I could confirm a number had 201 digits in 50 seconds.
But actually, I would only focus on the last 5 digits on the 201-digits number, as they should be sufficient to find the last 5 digits of the root.
I can't read a 200 digit that quickly
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... because his brain memorized something. Sure, he might not have known how he did it, but it wasn't magic.
Agreed, but if she has memorized some log tables PLUS has a gargantuan intellect highly specialized in mental calculations then things become clearer. I know that for example G65 - Grahams number - they probably will never figure out the entire string of numbers (needs more bytes then the entire universe can supply, probably even if you had total amount of particles in the universe ^ -||- amount of bytes) but they do know the last 500 due to patterns in how 3's multiply.
So she has a lot of those patterns in her head, as stated above, and can see what the last ~50 digits are up to and probably can rule out a lot of products. Even us laymen can see that the last digit is not an even number - doesn't get you to "...1". So that's half right there... or something.
What if we used bits with a higher base than 2?
Agreed, this is still insanely fast, even if you are able to calculate that in your head, which is dubious at least.
She probably had the log table memorized to a ridiculous degree and knew how to use it.
https://www.youtube.com/watch?v=vqbXPfaN_VM
You can use pretty basic number theory to simplify the calculation of the last few digits. e.g., you can compute the last x digits of any number raised to the power y without computing the whole thing.
Me too, I tried to do the calculations in my head and I got 1234 Potato
Also this is assuming the correct is an integer.
I think that was a given from the start.
You can get closer with things like knowing that powers of numbers that end in 5 all also end in 5.
My completely speculative guess is that she memorised a logarithmic table, so that she just pulls part 1 and 3 from memory. As I explained in my earlier comment, this was not unheard of. Part 2 is just division, albeit a fairly difficult one.
This method gets you close to the answer; an error of 225 puts you within .00001% of the real answer.
From that point, you do a binary search. Raise your estimate to the 23rd power (this can also be simplified), and if it is too low, add 512 to your estimate; if it's still too low add another 512, if it's too high subtract 256. Continue this process until you reach your answer. You can also use the relative distances of your "high" estimate and "low" estimate from your target to guess where between the two the real answer will be, to converge more quickly. Most of the time you won't need to check many numbers at all (in this case, around 8.)
Still a very impressive feat! But it's also neat to know how much seemingly intractable problems like this can be simplified.
Doing eight 23rd powers in your head in 50 seconds seems... challenging...
Definitely. It's still incredibility impressive; my only point was to explain how she may have made it easier. Doing it in your head 8 times is difficult, but it's much easier than doing it 555000000 times
When you get close enough to the number (like 225 away from the right answer), you can just start multiplying.
I think it's more likely she probably knew 50,000,000^2 and worked from there maybe.
http://i.imgur.com/jca3Z9Z.gifv
Thank you.
So far my biggest laugh of the day.
I've never seen that gif.
you might enjoy this one too
courtesy of /u/TheLandor
That man is really pretty.
Why would you link the gif version on gfycat?
This is much better.
sorry, I did not notice it was gif version, I just copied link that TheLandor used
The gif isn't very well optimized so it's rather large unfortunately.
maestro himself! great gif ;)
It's easier to read the text for the first time while the gif is loading.
WWWHHHHHYYYYYYYYYY
I miss Keenan and Kel
Same here buddy but this gif is from GoodBurgers.
i havent seen it in such a long time
hall of fame gif right there happy to see it again, nailed it
Glad you like it!
Imgr link isn't working for me, what was it?
It got me too.
Double the karma and gold for responding with an animated .gif to an incredibly-detailed and insightful post? Definitely on Reddit. :)
(Congrats on the gold, though! Just messing with you.)
Most of us understand and relate to the gif far better than the comment to which it was a response.
Oh I definitely get the joke. I laughed, too.
Haha yeah, I love the camaraderie on reddit. We can all come together and compliment each other on dank memes. Haha, we bond over means. Upmemes to you my memetastic friend :3
tips meme
I thought that "dank memes" was an adjective?
Dank is an adjective. Memes is a noun.
Separately, yes. But some seem to use the phrase as an adjective. Or is it like "the bee's knees" in which case it's just idiomatic.
Ahh man, I don't know tbh.
Laughed so hard at this. Thank you!
I peed a little
Laughed out loud. Nice gif.
Whatchu know about the leafy bug, sissy?
I'm giggling my ass off covering my mouth at work right now...absolutely perfect.
There will never be a better use. Might as well send this one over to /r/retiredgif
Edit: okay. No its not ready to be retired. It had to be so appropriate is absurd.
I dunno, this gif is pretty applicable to a lot of situations, I like having it on hand.
I've always wondered, how do you giffers keep these 'on hand'? As in how/where do you have them saved? Teach me thy ways.
[deleted]
thank you!
The hard part is to know if it was a retired gif
It is against the etiquette using a retired gif, you may even be banned from posting a gif ever again, so you have to be extra careful
Some people on imageboards have folders with thousands of pictures and then subfolders for specific theme for example.
I'd say its /r/DamnNearRetiredGif
/r/backfromretirementgif
I have yet to see it as applicable as this.
[deleted]
That subreddit gets spammed way too much...
Enlighten me
That is not eligible for /r/retiredgif.
Usually the gifs are only retired when the content is so directly applicable it's absurd. If this was somehow changed into a writing prompt where someone explained it to Eddy Murphy I think that would be more in the spirit of the sub. In this case it just seems to be an incredibly apropos use of a Gif, borderline retire-able, but just not there yet.
It was used today on the Super Mario WR video for near enough the same thing. Just because it's been used appropriately doesn't mean it should be retired. How is Eddie Murphy represented in the post?
Pull your head out of your ass La Fleur.
I am ashamed
Retired gifs have to be directly related to the post. Like if he had said "this math is so easy Eddie Murphy could do it" then you would be on to something.
It is still a great application of the gif.
Beautiful! /u/changetip /u/sc2math $2.00
/u/sc2math, Atlas_84 wants to send you a Bitcoin tip for 8,536 bits ($2.00). Follow me to collect it.
ChangeTip info | ChangeTip video | /r/Bitcoin
perfect
Seriously this is my favorite reddit post ever.
Would give you gold if I weren't broke.
Haha, my reaction exactly
U have been subscribed to math facts
That is such an incredibly useful gif.
whats this from? he looks older
Rofl Sir! Have AN Up Vote.
It's sad to me this has more up votes than the above comment...
Why is it sad? I would guess most people would have felt similar after reading /u/sc2math's thorough breakdown of the problem. I know I did. That gif perfectly summed up how I felt reading through it.
I agree, it wasn't simple and certainly confused me to a point but it seems like the comment was very high effort and high quality while the other just posted an appropriate gif. I'm not hating on the gif, I up voted it. I'm just saying that the explanation deserves just as many up votes if not more.
They hate us cause they anus.
reddit is a shittier version of high school sometimes.
Here's (1/2) Gold for you: /u/changetip /u/ThouArtNaught $2.00
The Bitcoin tip for 8,524 bits ($2.00) has been collected by thouartnaught.
ChangeTip info | ChangeTip video | /r/Bitcoin
ahahhahha you're so sad
Better fuckin be Eddie murphy
Ill have you know, I've never upvoted a comment before. You just earned p.impunity version of gold.
Your name isn't pimp unity? That's disappointing. I've always felt pimps need to learn to stand strong together.
Keep the hands firm!
wow so funny and original, thank god reddit is filled with people like you who repost these HILARIOUS meme images over and over again!
The sarcastic comments bitching about reposts aren't very original either.
the last inverse log i witnessed was a german video on motherless.
I tried searching for an inverse log sex position on google, so i typed "inverse log sex" and google: "Did you mean: inverse log x?"
God damn google is a prude
I'm not so sure it is a "sex position" but more a term that sounds about right for videos where someone takes a poopy in another persons butthole.
Even with SafeSearch on.
Use Bing for porn. You're welcome ;)
Even with SafeSearch on.
( ͡° ͜ʖ ͡°)
Sometimes I wake up thinking I'm a fish.
link please
At work right now. I imagine some simple search terms along the lines of "shitting in pussy" will eventually lead you to the promise land.
omg
I'm so much more ok with our beer stereotype ;_;
Why do you get to ignore the other ~~187~~ 196 digits? If we're looking for an exact root, is that much rounding really ok? Otherwise that makes sense.
EDIT: Wrote 187 instead of 196. and a word.
Well, if you know it's an interger you just have to look for numbers that are near your estimate.
The thing to remember, the 23rd power of something is going to be a huge number, 3^23 = 9.4143E+10 4^23 = 7.0369E+13, 5^23 = 1.1921E+16 - since you have an integer answer - you just have to find an estimate close to an int.
I suppose it might be irrational, but then it would have to some nth root with n < 23 of some integer in order to have an integer final solution be an integer.
But n would have to divide 23 and 23 is prime, so the 23rd root must be an integer.
Heh, I hadn't thought of that.
In general, the number is irrational (see sqrt(2)), so you have to stop somewhere anyway. If you want a more accurate answer just use more decimal places in the computation.
But how would the women then be able to provide an answer?
Yer a wizard, Devi.
Because they only need so much accuracy. Do you type out trillions of digits for Pi r^2 or just use 3-9 digits.
well if you don't care about getting the right answer...
That's a different kind of question because it is dependant on the relevance of the answer. Quiz questions are per se practically irrelevant.
A quiz show would address sig figs for that exact reason though.
That's my point though. Even though it's insanely impressive, it's still way less impressive than what the OP's title claimed then. If her answer is applicable to any 201-digit number starting with 55745.
Are you saying a 201 digit integer is somehow irrational?
That's how logs work though.
He moved the decimal over 200 places, and re-wrote it as
log(5.5745 * 10^200)
hence his explanation of
Since log(a * b) = log(a) + log(b),
Which means log(5.5745 * 10^200) = log(5.5745) + log(10^200)
log(10^200) simplifies to just 200
He didn't exactly ignore the other digits, he recognized them and treated them as trivial. They weren't all exactly trivial, but since we know we're looking for a whole number, once he uses enough of the numbers to see that the answer is only moving in the tenth's place, he can tell what the answer is going to be.
He needed less than 5 more of the 196 remaining numbers to get to this point, so we know that for the purposes of this exercise, at least 95% of the number was garbage information, only there to distract you. If they had used a non-integer answer, slightly more of the exact numbers would have been needed, but only enough to find one decimal place more than their answer required.
5 digits is enough for a lot of applications. If you need more you'd ignore fewer.
http://i.imgur.com/gL45334.gif
Exactly.
I need that to be made into this.
That's freaking creepy. I thought it was a still-frame
Dude thats freaky as hell
What bird is that?
Shoebill
Yeah like now its fuckin 2+2
Not much harder, just add in multiplication and division.
21?
What's incredible is that devi had no formal math education. No one ever taught her what logs are
Actually, that might have been what led her to be able to make the calculation. Research suggests people naturally count in logarithms before formal math education.
wow, interesting read
Logarithmic growth is a very natural progression. It occurs in music, economics, disease spread, genomes and so on. The natural logarithm is even far more interesting too.
Much of our sensing/neural processing also appears to be inherently logarithmic, e.g., vision, hearing, etc. A major reason for that is that logarithmic sensing enables scale-invariance. It's a very robust way of sensing, i.e., changes in scale due to changes in the environment (temperature, pressure, etc.) have a negligible effect on your ability to sense.
Logarithmic thinking likely rewires your brain differently from sequential thinking. Is there a way to unlearn conventional math education?
Alcohol?
Respawn?
Can you explain this?
As an example, since log(a * f) = log(a) + log(f), you could apply the nonlinear map log(a * f) and eliminate "a" and isolate "f" through filtering, e.g.,
g(x,t) = a(x(t)) * f(t)
log(g) = log(a) + log(f)
high_pass_filter( log(g) ) ~ high_pass_filter( log(f) )
exp(high_pass_filter(log(g))) ~ high_pass_filter( f )
where g(x,t) is the raw sensed measurement, the scale a(x(t)) is a function of parameter x(t) that slowly varies as a function of time t, multiplied by the desired signal f(t) whose bandwidth of interest is of a higher frequency. This is typical of many sensors whose scale / sensitivity, a(x(t)), depends on slowly varying local environmental factors, x(t), and the signal of interest is relatively fast, e.g., vision systems.
This simple process can be generalized further.
That's really interesting!
Of course, then she also did this problem "On 18 June 1980, she demonstrated the multiplication of two 13-digit numbers—7,686,369,774,870 × 2,465,099,745,779" which she managed in 28 seconds.
That can also be done with logs
log(a * b) = log(a) + log(b)
No idea if that's how she did it, but it uses a very similar technique to the root problem.
That just means we naturally have a sense for orders of magnitude.
For instance if I asked you to estimate if there were 10, 100, or 1000 people in a crowd of 500 you would be able to tell me instantly....more than 100 but less than 1000.
But if I asked you if there were 400,500,600 you would have a harder time.
This article is making me shit my pants. Math interests me a lot, and this is just cray.
I would rather say that it's the algebraic mean between 1 and 9. I've never heard it referred to as being logarithmically in between.
I'm sure she knows what they are. No matter how fast her brain works it still needs a route to find the answer. It isn't like shes just pulling the answer out of thin air.
exactly. She must have invented logs and other math concept most people need to be taught on her own, most likely without realizing it, because it's intuitive to her.
she probably got her hands on some math books and was self taught. you should read about the mathematician ramanujan, that was basically his story.
Ren and Stimpy taught me about logs.
I dislike how people use the lack of a "formal" or higher level education as a way to either discredit or accentuate someone's knowledge. When an employer hires someone with a degree, they're not hiring them for a piece of paper and 40k in debt, but rather a set of skills and knowledge that the paper says they likely have and can use. It's not impossible to gain these skills and posess said knowledge through personal study and hobby work, or other means. It's obviously easier most of the time to learn esoteric material at a higher level educational institution, but at the same time not impossible to learn medieval European history in your attic with encyclopedias.
You're misunderstanding. I'm not saying she didn't attend formal higher education. I'm saying she didn't have ANY formal education, period. Most people in the west build a base of understanding in middle school and high school, on which they can expand either through higher education or self study if they so choose.
Devi on the other hand, grew up in rural India and didn't attend school at all as a child. If you read the article, it says she was working with her father at a circus when they discovered her abilities at age six.
I 100% agree with your point that university is not for everyone and you could get a comparable education on your own. The reason I think Devi is incredible is because nothing, not a classroom or a book taught her how to do this. She didn't self study how to do mental math, it's an inborn ability that's intuitive to her.
If she is indeed using logs like OP suggests, then it means she interdependently invented logs on her own, most likely without using it, because it's intuitive to her. You have to admit, that's impressive.
[deleted]
[deleted]
What?
Basically, if you can't work out the 23rd root of 16748676920039158098660927585380162483106680144308622407126516427934657040867096593279205767480806790022783016354924852380335745316935111903596577547340075681688305620821016129132845564805780158806771 using this method you have the mental capacity of a brick, it's that easy.
Brick with a degree in math here.
They don't teach you numbers in calculus class here. All I see is F's, G's and x's
If you studied harder you could get that F up to a D. Derive all the functions.
Or just F THE D instead, probably get you further in life anyway.
can't forget u and v
And the entirety of the Greek alphabet.
Now I know my α, β, γ... next time won't you derive with me?
You should have studied (and mastered) log tables by grade 9.
No one does log tables in the age of calculators.
Blonde, brunette, redhead..
Something, something X. Fuck Jenny
Quite a few y's these days as well I hear.
If you had a degree in math you'd realize that arithmetic =/ math. As a mathematical physicist, I work with numbers less often than a journalist.
What is it you work with then? What is math if not numbers? Not trying to be a smart ass I'm just very ignorant on the subject
Functions mostly. A simple one I used yesterday:
f''(t) = a
f'(t) = v + a*t
f(t) = 0.5*1t +vt + p
A function and its two derivatives that gives you the change in position of an object with known velosity(could be 0) and previous position, when applied random accelaration over a period of time. This is how i'm calculating the change of positions in a game in a school project.
Functions and mathematical operations and operators on functions. I literally haven't written a number in my own work for longer than I can remember. (Besides something like x^(2).)
Surely any maths student has done number theory and challenged themselves not to use a calculator?
In that case, all you need to know is that for every real number x >= 0 and every natural number n there is exactly one real number y >= 0 s.th. y^n = x.
Taking my math minor right now. Pretty sure after calculus 2 you stop using numbers.
Please explain why Division by zero is not zero.
Okay. Division is, to put it in elementary school terms, taking a number of things and dividing evenly it into a number of containers, and reporting on how full each container is. That's where the remainder idea comes from when you're working with whole numbers. You've got 20 things, you're putting it into 7 containers, you'll have 2 in each with 6 left over. However once you get past that and you learn you can break the thing you're dividing into smaller parts, and since we're decimal here we'll break it into increasingly smaller increments of 10, your 6 left over becomes 60 tenths which get divided into the 7 containers with 8 tenths each, with the 4 tenths left over divided into 40 hundredths and distributed 5 times each, then 7 thousands, 1 ten thousands etc or 2.857142857142... written out like big boys and girls do.
So with that understanding in mind here's your problem. I'm going to give you 20 things and I want you to divide it among 0 containers. And no remainders, I want the decimal answer. Go.
Do you see the problem? You can't even get started. No matter what you do you have no place to put the things you're trying to divide up. So you're stuck. No answer, invalid question.
Extended answer in the comment below this one.
Extended comment to the above. If you're satisfied with the answer above then stop here. Because here's the part where I try to blow your mind, and you didn't even ask for that.
You know how when you were first learning the number line you were shown:
0, 1, 2, 3, 4 -->
Like that with an arrow pointing to infinity? And you were shown addition on that number line (start on the first number and count towards the right the second number and where you land is the answer) and then you learned subtraction but you were told that if you ever try subtracting a bigger number from a smaller number you can't do it because you're going to fall off past the zero, so just ignore those question.
And then your number line got expanded with these strange things call negative numbers and looked like this:
<--- -4, -3, -2, -1, 0, 1, 2, 3, 4 -->
And suddenly you could do those problems you were told to ignore. You can subtract a larger number from a smaller number, the answer just goes negative. And your mind was blown. And then you got used to the idea.
Then you learned multiplication, and it happily fit on the new number line. And then you learned division and you were told that if you have leftovers to just stop because it didn't fit on the number line you were shown.
Then you were shown fractions and decimals, the numbers between numbers. And suddenly that number line had an infinite number of infinitely small spaces between each number where new numbers could reside, even numbers that never terminated, like the result of 20/7. And your mind was blown. And then you got used to the idea.
And then you learned about powers, repeated multiplication, and it happily fit on your new number line. Then you learned roots and you were told that if you were ever asked to take the even root (square root being the most common example) of an odd number to just ignore that answer and stop.
Then you learned about i. You were told that there was this imaginary number that was the square root of -1 and you could solve the problems you were told to ignore. And your mind was blown. And maybe you got used to the idea, maybe not.
For most of you this was the limit of your math experience. And what you didn't know was that ever so quietly your number line was once again expanded and it looked like this:
4i
3i
2i
1i
0 1 2 3 4 -->
-1i
-2i
-3i
-4i
Had to cut off the negative real numbers, but they're still there. So an answer that looks like 3+2i can be plotted on this number plain. That's one number composed of a real part and an imaginary part.
With imaginary numbers the number line has become a number plain and this is the realm of advanced mathematics and fractals and really cool stuff. There are cool things that happen to numbers on this plane. If you do mathematical operations with imaginary numbers they move around on this plane in 2 dimensions, sometimes in wild ways. Roots of polynomials form pretty shapes. And it messes with some mathematical operations like how do you determine which is greater, -3+3i or 3-3i? Tons of college level math happens on this number plane. It blows your mind, and eventually you get used to the idea. A little bit. Still blows my mind at times.
Still with me? Something's wrong with you, but okay, here's the part where I bring it back around. There is a 3rd dimension to the number line and it is the domain of X/0. Yes, divided by zero is, if you make it this far down the rabbit hole, a problem we can find the answer to. Kind of. Sort of. It's not as straight forward as imaginary numbers expanding into the 3rd dimension and plotting points. There's no shortcut symbol we substitute for 1/0 and call it all good. Answers aren't points but fields, areas where the answer can lie. This is a wild and untamed field of mathematics with limited apparent application so it has remained largely unexplored. It's the perfect place to look for a doctorate thesis, though, if you're interested in that sort of thing. Because as far as I know it's still blowing people's minds and no one has gotten used to the idea yet.
What is this area called?
The extended complex plane.
What a great answer. I will be using this one for when people ask.
http://i.imgur.com/jbigcKa.png
I should change my job description to Software Developer Brickgineer
No, no one's saying that it's just easier than it looks.
You and I have drastically different meanings of the word "simple"
I'd imagine that he means simple relative to the brain capacity of an "Indian mental calculator"
7.
Exactly. I think.
Yeah no kidding, I think the right words are "just very slightly less impossible"
I think he's just trying to feel smart
Well, relatively simple and probably similar to the method she used. The super computer probably did it the hard way.
The question is, how much dB simpler is this solution?
http://upload.wikimedia.org/math/d/8/2/d82ce9c9174bad8327e08e93491457ca.png
What?
http://upload.wikimedia.org/math/d/8/2/d82ce9c9174bad8327e08e93491457ca.png
wat
http://upload.wikimedia.org/math/d/8/2/d82ce9c9174bad8327e08e93491457ca.png
waittt whatttttt?
[deleted]
..........
okay
Let's just go home.
[deleted]
Yeah uh, he isn't feigning.
[deleted]
It's the purple kind.
Like sc2math upthread said — just logarithm operations.
I have no idea either but I could find two useful wikipedia articles in simple english: http://simple.wikipedia.org/wiki/Logarithm http://simple.wikipedia.org/wiki/Exponentiation
How old are you?
I'm assuming you either use math beyond very basic algebra routinely or you are still in school.
The whole "use it or lose it" thing is true. I'm a college educated, successful 25 year old and I don't remember how to go about performing the operations in that equation because I haven't had to do anything like that in almost a decade.
Yeah, I'm 32 and don't think I've ever eve seen anything like that. Then again, I made it through college only taking 2 math classes.
[deleted]
It's Algebra II. Here's a link to online classes for them if you are interested:
https://www.khanacademy.org/math/algebra2/logarithms-tutorial
I don't think it has anything to do with age but whether you learned it/about it or not. I am 28 and I have never even seen anything like that.
It's stuff you learn in high school.
No one who has been out of high school for more than a couple years, and doesn't need to use math at work, remembers anything about high school math.
That's probably true. It's funny how people fall over themselves to talk about how much they don't remember it or understand it though.
I don't remember much about the plot of Richard III, which I read with my class in the ninth grade. If I saw a discussion about that play here, I can't imagine my first reaction would be to post about how I don't remember anything about it, and how I don't understand Shakespearian English.
[deleted]
[deleted]
I'm sorry to hear that.
[deleted]
I deleted my comment above, because, yes you're right, it is a bit mean spirited. However, I do want to respond to you:
I get that not everyone knows everything, I am aware of the gaps in my own knowledge. I am totally totally on board with two kinds of attitudes when encountering something unknown:
"Hmm, I don't know this, but this is interesting, I want to know more", replies phrased like "can you help me understand this" or specific questions about the content fall into this - I spend a lot of time on /r/explainlikeimfive and /r/NoStupidQuestions helping educate exactly these kinds of thinkers
Hmm, I don't know this, but this isn't relevant to me, or I don't care enough, so I'll ignore it and move on - totally valid as well.
The attitude I have a problem with is the one that celebrates ignorance. "Hey I'm dumb and I'm cool attitude." Often responses like "What?", "Wut?", "Wat?", "I understand some of these words" etc are reflective of this and grate on me.
Anti-intellectualism at its finest.
[deleted]
The reaction is one of unwillingness to learn.
"Oh, this is too complicated for me. I'm going to play up how dumb I am instead of taking the minimal effort to understand it. LOOK GUYS. I DON'T KNOW SOMETHING. LOL RIGHT?"
Formula for brick. That's how bricks are calculated into existence.
Erm yeah ofc. If we have that log(a^b) = b·log(a) then of course.
Why is this not in my textbook... Would have saved me on my exam
I'm pretty sure it's in every highschool math textbook.
Here you go, a nifty formula with weird signs and such.
Logs. You have to learn them in algebra II in highschool.
I'm 21 years old. I'm a programmer. I did 2 years of Comp. Sci. in college.
I still don't know how the fuck logs work.
guys... Logarithms are just inverse exponents. Log base 9 of 81 is equal to 2 (since 9^2 = 81)
I'm on alienblue which apparently doesn't show carats. So your final statement showed 92=81... Which I'm pretty sure is not true. I know enough math to debunk that one.
Are you sure? How long did you go to college for?
Okay, tough guy. Prove it.
Sigh, I got this far into the thread wondering why none of the math was making sense
This equation works in hebrew, which is read right-to-left:
18 = 2 * 9
Ah. The Jews once again demonstrating that they know things that common men can never understand.
Reddit automatically turns carats into "super" html tags.
The 2 is a superscript. 9 squared.
HE SAID HE KNOWS ENOUGH MATH TO DEBUNK THAT ONE
edit: Upvoted for being a dick. Thanks, reddit!
oohhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh
Dunno if you really want the answer, but here goes
Log-base a-of b=x is basically to be read as 'a to the power of x=b'
So you're asking a to the power of 'what' gives you b? So, log-base 10-of (100)=2, since 10 raised to the power of 2 is 100.
This brings back almost PTSD like memories from high school tests.
I understand the concept. But I can't break down a log into a series of smaller functions.
If I forget 9*8, I can instead do 9+9+9+9+9+9+9+9
If I can't remember what 8^3 is, I can do 888.
If I can't remember what 72/6 is, I can do long division.
If I can't remember what Log(47) is, well, fuck me.
Dunno if you really want the answer, but here goes
Log-base a-of b=x is basically to be read as a to the power of x=b
So you're asking a to the power of 'what' gives you b? So, log-base 10-of (100)=2, since 10 raised to the power of 2 is 100.
So in your question you're asking 10 (assuming base 10 log) to the power of what is 47? Or 10^x = 47.
I also know that. I can't write it out and figure out what it is. I still have no idea what the answer is. I would have to use a table or a calculator.
Ah. Same here.
You can estimate pretty easily though. You should know pretty much immediately Log(47) [assuming log base 10] will be less than 2 and larger than 1, because 10^1 is 10 and 10^2 is 100 and 47 is in between. It is the same exact process as 8^3 = 8*8*8.
Soooo... where would I go from there? There are a large amount of numbers between 1 and 2. How should I go about narrowing that down? 10^1.5, 10^1.7?
When I don't know what 713 x 567 is, I don't figure out 700x500 and 800x600 and try and narrow it down from there. I multiply the two out.
To get an exact answer you'd have to use a logarithm table. Logarithms are used for complex shit that simply can not be done in your head. But it is very easy to know what a logarithm actually is. That was my point.
I know, but I want to know how they're calculated. Give me the formula for them. My calculator most do SOMETHING to figure out random log like log(3840834.35235). If I had a pen and paper, I should be able to do it too.
Edit: I have the same grief with sin, cos, and tan function.
There is no easy method to do logarithms by hand. They involve the use of Taylor Series (calculus) and even then still require the lookup table. Computers actually perform logarithms by lookup table as well. Way back when before calculators were a thing, logarithm tables were a giant sheet of answers you had to spend 20 minutes looking at to compute it. You COULD do all the calculus to do it by hand but its absolutely tedious and pointless. Trig functions use Taylor Series (calculus) to get their answers as well. Nobody does these by hand. If you want to better understand trig functions then study the unit circle.
I do understand the trig functions through the use of the unit circle.
How did those giant sheets of answers come to be though? What is the fundamental, most basic, aspect of Log calculations?
You already know what the most basic aspect of log calculations are, its inverse exponents. It just happens to be fucking insane to calculate accurately. The table is made of pre-found answers that were done by tedious calculations carried out by top mathematicians so you wouldn't have to spend months doing them.
Basic idea is inverse exponents like I had said before.
Actual calculation (of non-trivial cases) requires calculus the level over the heads of most humans alive today.
Its a hard concept to imagine I guess, but mathematicians do very little arithmetic. Arithmetic (the branch of mathematics dealing with the properties and manipulation of numbers) is considered by most mathematicians to be trivial. When you get to the upper echelons of math, it isn't about finding the solution, it is about proving that a solution to a problem exists. The reason these tables existed is because mathematicians looked at the discovery of logarithms and how they can be used to do all sorts of magical calculations, and realized they're fucking insane to calculate. They realized very fast that calculating these by hand would be absolutely ridiculous every time, so a couple of guys who were working very closely with the discovery of the logarithm created this master table of solutions. You have to get over the idea that you should be able to do everything in mathematics by hand, it just isn't the case [well, you could, but it would just be an exercise in understanding. Otherwise you're just reinventing the wheel.]. It is just how the math world works; one day's mathematical breakthrough is the next day's homework exercise.
You can read more about the history of the logarithm here in this short 2 page article: http://www.britannica.com/EBchecked/topic/346146/logarithm
I understand that. I want to know how for knowledge sake. I know the Taylor series and how that works too.
Overall, I just would like to know. An itch I would love to scratch.
I think they use a method of approximation, where you repeat a calculation over and over to arrive as close to the answer as your precision requires. That's why it's hard to do by hand (calculate a log). It's a form of infinite series I believe.
what's the log ^^^9 of 99?
log base 9 of 99 ~= 2.09132916932
since
9^2.09132916932 ~= 99
nice! Thanks
Roots are inverse exponents. ^(2)√81 = 9
Logs are black magic. Here, take 9 and 81. Now good luck finding what exponent you use to get there, as there is no simple set of steps for that.
It's just because you're more used to one than the other. ^(2)√81 looks easy because you have a bunch of square roots memorised. But if you want ^(2)√563, you bring out the calculator. However, ln(563) is no more complicated to calculate than ^(2)√563. Square roots are actually quite time-consuming to calculate. At high school, you never actually learn how to calculate a square-root, instead you basically memorise a bunch of squares, or you use your calculator. You really need a multiple step algorithm if you want to calculate it by hand, which is exactly the same as what you need for calculating a log.
I mean, for your example, the log is pretty simple too. Your first problem is ^(2)√81=x, and we know that x=9 because we have 9^(2)=81 memorised. For the log, it's log_9 (81) = x, which is another way of saying 9^(x)=81. Again, we know x=2 because we have memorised 9^(2)=81. They're really on the same level, it's just that square roots are more familiar, and thus seem less "scary".
http://math.stackexchange.com/questions/956776/whats-the-inverse-operation-of-exponents
no
Although it is not the top answer, one answer says that both are. Other answers mention roots, while some others mention logs. So I guess we're both right?
No.
Roots are the inverse to power functions, i.e. functions of the form x^n .
Logarithms are the inverse to exponential functions, i.e. functions of the form n^x .
Tantamount to how exponentiation is consecutive multiplication (which is consecutive addition), logs are consecutive division (which is just consecutive subtraction).
It was more no to "logs aren't inverse exponents"
which is what I thought you were insinuating. Like I'm a CS major too and I hate math too, but I always thought logs were a pretty simple concept..
I was, in fact insinuating it, to be honest. So thanks for correcting me, anyway.
Roots are the inverse of x^n = y. Logs are the inverse of n^x = y. They are fundamentally different.
[deleted]
Drops out*
Could be 2 years of general education and 2 years of computer science
The thing is, you can't get through comp Sci without understanding logs, as so many algorithms have their performance bound by log(n). Most likely he got to data structures (which can be a sophomore year class) and dropped out, which I think he was implying himself.
There is a difference in knowing how to use something and knowing how it works.
You have to understand logs to get through comp science. How are you going to use the math in a field where not everything is clear cut and all you do is plug in formulas if you don't understand it. The "math" taught in most public schools is nothing more than memorization, no thinking required.
When we're looking at something as low level as logs I don't think that's true. That trite statement only works when there are abstractions in place.
Completed science degree here. Never have even seen log(n).
Pro tip: Community colleges are horrible.
I wanna say you're getting scammed but at least CC is cheap.
redditor confirmed
... Two years of comp sci in college does not equal 2 years of college. That being said, Fox News may have an opening for you.
Ya but it means he probably flunked out or changed majors.
Wait what? Lol. You's trollin.
I've taken 2 years of accounting and I'm not in school to be an accountant. I've taken 2 years of auto shop and 2 years of Spanish and I didn't intend on either of those having a major role in my future. You have space to fill out some credits with electives. Taking a few semesters of comp sci, especially when in school for a stem degree, is nowhere near out of the question.
Also it's super elitist to act like that even if they did leave school. Snob.
If you told me you had taken 2 years of accounting in reference to not understanding math, I would assume that you can't handle the subject and quit for something easier.
That's a poor assumption. Math in accounting is rudimentary and nearly impossible to fuck up. I was a C student in algebra and I failed precalc but i have a. 4.0 in all my college accounting classes. I took accounting at night actually, so I was in class with a lot of ladies who worked at the local banks, and they actually looked to me to help. And again, I'm garbage at math. Also curiously I'm great at physics which is just applied precalc. Got an A in physics but an F in precalc. Go figure.
Also worth saying that changing paths might reflect that you found a new passion elsewhere, or decided that you didn't want to do your original major as work for the test of your life (even if you're decent at it) so you switched to something else. I think this happens a good amount.
Or that he realized that you can study on your own and still get employed. Experience is a greater demonstration of knowledge than a paper that shows what school you went is, in the CS industry.
Ohhhhh shit he brought up fox news! So original! Good one
Was trying to be relevant, not original. He may have been joking, but still, he rewrote the whole quote to fit what he was saying. That's a Fox thing to do.
Also in general making fun of people because they don't have as much school as you is elitist. But I suspect that he was joking more than anything, so I made my Fox News quip instead of trying to call him out.
It's just old to me I guess. I've not watched fox news or read an article from them in forever. It's really easy to do if you don't like them
Community college computer science... I don't even want to know
edit: so many mad Associates in here
Something like this
I'm a multi-billionaire math professor and have been teaching math for 30 years and I won various math-related awards and I still don't know how logs work.
[deleted]
Burnin' down trees don't make you a lumberjack buddy
Dexter?
Dexter AKA BONGLORD420
Are you OK?
nice.
Are you ok?
Do you sleep all night and work all day?
BONGLORD420 is on the case... at the crack of noon
He's a lumberjack and he's ok.
Because trees. I get it.
Ironically, what you have in common: you both wear suspenders, high heels, and a bra
I'm not sure I believe you. College professors don't make that much money.
You should consult a lumberjack.
Miley. Fucking. Cyrus.
If you're a multi-billionaire maths professor, you're either doing it very very wrong or very very right.
did you acquire your wealth by being a math professor, or is that more of a hobby?
My gf though a multi billionaire would be helicoptering into inaccessible snow places, skiing down them, to have their driver waiting at the bottom of the slope with a change of clothes ready to take them to an small field where their helicopter would be waiting to take them to their fuck-off huge yacht for dinner made by Blumenthal with a bunch of scantily clad hot bodies moving seductively around them as they ate.
I said they would be on reddit... I was right!
Well, log base ten is basically going to give you a whole number and some trailing decimals (if your number isn't a power of ten). You can predict the whole number part because it's the length of the original number minus one.
So, log(10) = 1
log(100) = 2
log(1000) = 3
Log(500) is between 2 and 3
The log of her number is 200.something because it's a 201 digit number.
logs are a way of writing astronomical numbers into shorter, more compact versions of the same numbers. They tell us the order of magnitude something has changed by. If a magnitude increases by exactly one, that means the new number is ten times bigger than the last one. If log(x) = 5.667, your number x would be the number 1 that has grown 10 times it's size roughly 5 times (1*10*10*10*10*10), so you can already know just by seeing the log that your number is already beyond 100,000 times the original. So, logs can find exponents that can be used in place of scientific notation which is convenient for things like growth and decay rates or star stuff.
That can be done like so:
Using the the value from the log: 1 x 10^5.667 = 10^5.667 ~= 464,515
Using scientific notation for the same number: 4.64515 x 10^5 = 464,515
Please note, logs are far more complex than this when you get into different bases (such as "e"), but I'm just trying to explain the easiest to understand base for most people and the one most people without an understanding of logs are likely to have been exposed to.
Logs are better than bad, they're good.
Edit: clarified a little bit.
That answer made a whole lot of difference more than "It's just a reverse exponent". It actually teaches something, rather than re-stating the dictionary definition.
Thank you. I had to play with them for some years before I was able to "visually" understand what was happening, I'm glad it helps.
Whatever he said.^
Sick reference, bro
Don't worry, you can be a web developer!
Er...
About that... My SublimeText window right now: http://i.imgur.com/GpFzkwv.png
How the fuck do you do two years of Comp. Sci. and never encounter a logarithm?
You should really work on that. It'll save you some trouble someday. They're just the inverse of exponentiation.
Senior undergrad Immunology/Microbiology major... yep.
Apparently you didn't do very well.
I dropped out, but that was because I moved to another city. (It's not like in the US where people move into their universities).
I'll restart in a different university next year, though.
You should learn about the Big O sooner or later, understanding 'logs' there isn't fundamental, but it's going to help so much understanding certain concepts.
Not just that, but log2 and 2^x are both very important in a binary world, AKA computer science
You should still understand how logs work. Especially since most math is learned in the first two years.
The only math I learned in college was Discrete Maths.
I had Calculus I, Vector Calculus and Linear Algebra. Doesn't mean I learned them, but I had them.
you get this book with numbers in it that you accept are right and then add or subtract various 'logs' e.g 'sin', 'cos' and 'tan' respectively the sine, cosine and tangent of something
And by changing 'normal' numbers into 'logarithmic' numbers, you can do all sorts of difficult calculations using only simple mathematical functions to obtain crazy precise numbers of ... stuff
it works, brick here, don't ask me how!
Logarithms are reverse exponentiation. How can you be in CS and not understand them?
As you may (or may not) know, computers only do what they are told. Your algorithms must be shit if you don't understand how to deal with manipulation of large floating point numbers or decimals without rounding errors (computational complexity theory), and also time complexity. That's the point of the OP saying "[the] US Bureau of Standards [wrote] a special program ... to perform such a large calculation." They brute-forced it, which is usually never a good idea.
If you know the theory and can use log tables, the solution reduces to "simple" mental arithmetic. It's a parlor trick (by a very skilled mathematician, no doubt). Check out http://projecteuler.net for some other good computational challenges. On some of these, no amount of CPU cylces will crack them. It often takes a clever solution to solve.
For my money, Ramanujan is the #1 Indian mathematician.
It pushes the x down from the b... or something.
logs seemed to be an afterthought in all my education as well. Kinda tacked on the end of HS Calculus, Uni Maths. Then mentioned as kinda bonus questions in exams.
The kind of stuff I didn't ever commit to memory, therefore never needed to purge it either....
It's the inverse of a power function. So just like how division and multiplication by the same number would reverse each other (ie you'd get back your original number), so do powers and logs in the same base.
If A^x = Y, then Log(Y) = X
Note: the base of that log function should be A. I couldn't figure out how to do subscript
Addition/Subtraction
x + y = z.
What do we add to x to get z?
z - x = y.
Multiplication/Division
x * y = z what do we multiply x by to get z?
z / x = y.
Exponentiation/Logarithms
x^y = z
To what power do we raise x to get z?
log-base-x(z) = y. (If there is a way to subscript on reddit, someone please let me know)
What's the log2(256) = 8
log2(1024) = 10
log2(65536) = 16
Basically, log2(x) is how many bits do you need to hold a number. Now pretend you can have a fractional number of bits. log2(1000) = 9.9657 <- this number is calculated by tables. How does it work? Who cares.
What we know, is that logs have interesting properties (how do they work? I have no idea)
log(x*y) = log(x) + log(y)
log(x / y) = log(x) - log(y)
log(x \^ y) = y*log(x)
log(yth root of x) = log(x) / y
This works with ANY base. It could be 2, 10, e, etc.
So, what sc2math says is that if we apply the logarithm of the formula, we can simplify some operations. Then we exponentiate and ta-da!
But I think he misses the point that to do that ALL in your head, you'd need to be able to calculate logarithms and exponentiations all in your head, too. I'm pretty sure the mental calculator woman did something else entirely.
I did 4 years of compsci in university.
I wouldn't have made it past the second year if I wasn't able to figure out how logs work.
Your story sounds legit.
Logs are a series of files that tell you what is happening with a program. Usually a programmer will write out errors to logs so that they can then have the logs sent to them when a program crashes.
Well, I'm very familiar with this kind of log
Using Dreamweaver isn't programming
Thankfully, I never touched it. Take your assumptions elsewhere, please
Just use a computer.
That's pretty bad. In Comp Sci. you should just take the taylor series at least.
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I can't believe you seriously expect anyone to believe that.
Agreed.
no wonder i almost failed that class.
It's actually not that hard. With log base 10, it's essentially just the "number of zeros" in a number.
So for example log(1) = 0 log(10) = 1, log(100) = 2, log(1000) = 3, log(10,000) = 4 and so on. The trick is that it's ~~"spread out"~~ "smoothed out" so log(20) = 1.30102999... log(200) = 2.30102999
etc.
So for example the "stair step" function in the number of zeros looks like this, while the "smoothed out" function looks like this
It gets a little more complicated when you have logs of different bases, like log base 2, log base 2.718281828... and so on.
http://imgur.com/iZthbNg
Log(100)=2*
Hmm. log(100) = 2
Otherwise your going to confuse everyone like Grot here
Yeah, it was a typo. I didn't even notice.
I only see two zeroes in 100, but you said log(100) is 3. And I have no idea what you mean by "spread out".
It was a typo. (fixed now)
By "spread out" I simply mean on a continuous range, instead of a "stair step" function
A "stair step" function in the number of zeros looks like this
while the "smoothed out" function looks like this
See the difference?
By spread out I think he means that the gaps between logs become smaller the higher the number.
Actually it means "no gaps" I probably should have said "smoothed out"
What?
log(1) = 0.
log(100) = 2.
Yeah, it was a typo sigh
nigga you missed a 0
It was a typo.
log(100) =2, not 3 :)
Hah! I must have hit the wrong key on my keyboard, and not noticed.
That can happen to anyone I guess. Have a nice day!
Not really, if you explain it properly it is quite intuitive. Trouble is it sounds silly if you don't make an example.
The base 'z' logarithm of 'x' gives you the exponent of a number in base z that is equal to x.
In mathematical terms: log z (x) = y <--> z^y = x
For example: log 10 (1000) = 3 <--> 10^3 = 1000
Logarithm in base 10 is so common it is usually just written lg (x). Similarly logarithm in base e (Euler's number, which is it's own derivative) is so common it is written ln (x), called the natural logarithm.
Err not usually, if f you are ahead you can get to logs but my algebra II class we did not get there at all.
Our teacher was horrible and we pretty much learned polynomial functions and matrices and that's about it.
Was really fucked at the start of this year with AP calc
So you base your "not usually" comment on your class that you admit was awful?
You're right. But I asked around a bit and none on my classmates that were behind a year learned it either, I think it just might be my shitty school
Sounds like the school to me. Did it offer anything after algebra 2?
Yes pre calc then AP calculus which I'm taking right now
A class being awful really has nothing to do with the subjects on the curriculum on a higher level. It may simply be that logs are not part of algebra II curriculums in some places. Same went for my school, and we had fine teachers and classes. Those things have no bearing on a designated, mandatory curriculum.
Algebra II honors covered logs but the normal class didn't. Why do I remember this...
Why do that, you can find all the logs you need in a forest.
I remember doing that but I have no idea what logs are or how they work. It was simply an act of memorizing symbols and patterns and formulas. That's what all higher math is to me and a lot of people.
And you forget them pretty much as soon as you graduate, unless your job involves heavy math.
The neck beards are out in hordes today
I learned more about logs from that comment than in school.
I got them in 7th grade - and never saw them again until Big-O notation in CS
I drop them occasionally too.
http://i.imgur.com/ZOqj3kz.jpg
That is a sweet ass table
edit IT IS A GOD DAMN LOG TABLE
Where is the jpg for sweet ass-table?
it's called math
not even once
It's actually called maths.
[deleted]
Burn
I just dropped a log. In the toilet.
It was poop.
THE PROBLEM IS ACTUALLY MUCH SIMPLER THAN IT APPEARS AT FIRST GLANCE IF YOU MEMORISE LOG TABLES
https://i.imgur.com/DrXpLu5.gifv
To the other replies so far
They're making a fucking joke
[deleted]
True, just that the replies seemed so serious, as if the "what" comment was an actual question.
I don't think this was a "I get it but I'm going to play dumb as a joke, tee hee" comment. Dude really didn't get it (or at least get it enough to get the gist).
And being ignint is cool.
What?
[deleted]
I didn't say it was a good joke.
[deleted]
You seem upset
Wow, making fun of the site you're a part of, that isn't overdone yet.
THE PROBLEM IS ACTUALLY MUCH SIMPLER THAN IT APPEARS AT FIRST GLANCE IF YOU MEMORISE LOG TABLES, WHICH WAS QUITE COMMON IN THE DAYS BEFORE CALCULATORS. YOU ARE TRYING TO FIND X1/23 TAKE LOG, AND YOU GET (1/23) * LOG(X) LET'S SAY YOUR NUMBER IS 55745.... FOLLOWED BY 196 MORE NUMBERS. SINCE LOG(A * B) = LOG(A) + LOG(B), YOU HAVE LOG(X) = LOG(5.5745) + 200 SO NOW ALL YOU HAVE TO COMPUTE IS (1/23) * (LOG(5.5745) + 200) = 0.043478 * (200 + 0.7462) = 8.728 APPLY INVERSE LOG, AND YOU GET 108.728 = 108 * 100.728 THE FIRST PART IS TRIVIAL, THE SECOND PART YOU CAN LOOK UP EASILY IN LOG TABLES (OR HAVE IT MEMORISED).
You just like, said what he said, but all bold and combined together, yet somehow I still think you're smarter than me.
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ALL BOLD CAPS
Was it a perfect root? Cuz if it was then yeah it does become waaaay mor manageable to the point that you may be able to infer the answer from important clues (like the last number being 5 for example can only be achieved if the answer ends in a 5 right).
I Googled the number really quick. Yes, so long as rounding errors are not an issue, it's a perfect root. However, I don't know how accurate Google is for such large numbers.
Yeah makes a huge difference, especially if she knew that it was a perfect root. I can say certainly that I know the last digit of that number: 1
Yeah, there's also a lot of other hinters as the first digit numbers.
1: 1,1,1,1...
2: 2,4,8,6,2,4,8,6...
3: 3,9,7,1,3,9,7,1...
4: 4,6,4,6,4,6...
5: 5,5,5,5,5...
6: 6,6,6,6,6....
7: 7,9,3,1,7,9,3,1...
8: 8,4,2,6,8,4,2,6..
9: 9,1,9,1,9,1..
Might be possible to determine the number like that pretty easily.
especially if you remember the rules for the second and 3rd place of every digit.
We know that the last digit is 1.
Therefore the next digit must be 3 ( 7 on the second digit.)
Edit: Actually, it's much harder. You need to know a two digit number (with the last digit being 1) which gives you 7 on the second digit when powered by 23. By calculating from 9^23 I think it's 9 but I'm not sure. since I did a lot of calculations in my head
then the next digit must be 5. (since the third digit is 7, and 3^23 leaves a 2 on the second digit. (Not too hard to calculate, since all you need is to carry whatever is left from the first digit))
Edit: Here you need to know a three digit number which ends with 91, which would give you 7 as the third digit when powered by 23. After calculating each digit ^23 on early digits I came up with 8. However, if you memorize each digit to the power of 20,15 and 10, you can calculate all of these at much greater speed than I did. And several of the digits are redundant (9 is 3^2, 8 is 2^3, 4 is 2^2, 1 and 0 are constant. And 2 are very easy to memorize (Anyone doesn't know how many bits in 1kbit?)). Also you need only remember the first 8 digits of these numbers (if they reach 8 digits).
And etc...
still it get's harder each step.
Might be worth on the last number or two to calculate using the first digit instead, although I don't think it's an easy series.
Edit: My bad forgot to carry the 9^23*1 and the following carry from earlier digits, so my calculations for 2nd and 3rd digit were bullshit. ( Though the theory in it is still legit, though much harder then I initially thought)
Shes a human calculator
She did
No I mean if that was given to her or if there's a relatively easy way to figure it out
Yea, she's sees some pattern
Otherwise how could she do shit like this.
It's all about pattern recognition to make yourself into a human calculator.
Yeah. Which is actually why I don't like that term. You're almost taking a good guess by elimination instead of doing what a calculator does tons of iteration.
Excel gives me 546372891.
In other words, you can treat it the same way someone with a slide rule would.
Very simple. Here, let me give you this 201-digit number you can give me 23rd root of in your head.
But why male models?
http://i00.i.aliimg.com/photo/v0/114590998/log_table.jpg
OK, I looked that up, what next?
http://i.imgur.com/vpNNJ1R.gif
[deleted]
Meth, just this once. Might actually help with the math.
This is your brain.
And this is your brain on math.
Wait. It's been forever since I've attempted math. Where did the 200 come from again? You said 200 (assume base 10). Please explain that step.
The 200 comes from the splitting the number into 5.5745 *10^200.
log(5.5745*10^200 ) = log(5.5745)+log(10^200 )
log(5.5745*10^200 ) = log(5.5745)+200
the number is the same as (5.5745.....) * 10^200
log (10^200) = 200.
Oh good grief. Thank you. That makes sense.
thats even more amazing
If anyone remembers, this is how slide rules, essentially the precursor to electronic calculators, worked.
Yep. They're basically just a quick way to do a lookup in the log table. They usually have a few scales on them so you have a couple different tables in one.
User name checkout.
But x is not 5.5745*10^200 is it ? Or was she asked to give an approximate solution?
Actually, you are oversimplifying the problem. The answer is an 8 digit number. So, you have to know the log tables and also to carry out all these intermediate steps to at least 8-9 significant figures.
This is the answer I was looking for. Not that I understand it at all, but uhhhh. Ya.
If you have some exponentiation to do, can you 'log it' once to turn it into multiplication, then log it again to turn it into simple addition?
One of my professors once told us we wouldn't need calculators for the final. Turns out he expected us to be able to do this and only relented when it turned out that nobody in the class knew the log table off the top of their head.
When I was in college I went to a used booksale and found a log table book listing just about every log. I was curious whether it was meaningful and worth owning for 50 cents or whatever. I asked my older brother who was just finishing his PhD in Mathematics and his answer, No, you don't need such a thing anymore in the age of calculators (which of course I was well into in the late 90s; this book was very very old).
Your explanation was very good.
R/theydidthemath
Without memorizing log tables would it have been possible for her to compute?
Is this how she'd probably have solved it in her head? Or some other magical way?
3D, adaptive, parallel computing power of your brain can do amazing things. We all can do these crazy calculations. It is really hard to get the answer out of our subconscious without confusing the signal since we are normally so stuck in the language part of our brain which has less subtle signals just from the reinforcement of pathways due to how we use our brains in day to day life.
Thanks Ender.
Ender?
Now I remember why I failed that class in high school
So whole special program thing is bull?
http://i.imgur.com/gfGdXBn.jpg
I thought you were just writing gibberish before taking a closer look. That's pretty neat.
http://imgur.com/gallery/RadSf
I'm sure the US government spent millions of dollars and dozens of man-hours creating a computer program to solve that equation, as the headline implies.
It's almost too easy.
You lost me at 'log'.
yea but she did this in 50 seconds
You lost me at "followed by 196 more numbers" = 200
Oh yes, this sums it up quite nicely. Very simple... I'll just be over here with my calculator trying to figure out how much my coupons are saving me if anyone needs me.
http://i.imgur.com/nCec3EU.jpg
http://i.imgur.com/nCec3EU.jpg
thanks for pointing this out
I doubt she had the logarithm of a random 201-digit number memorized.
I love meth.
I actually understand that, but there is no chance I could do it without a calculator
Log? https://i.ytimg.com/vi/2C7mNr5WMjA/hqdefault.jpg
So how come the US Bureau of Standards had to write a special program to perform such a large calculation?
Obviously, duh. Learned that shit in like the 3rd grade
Are you a maths teacher/professor?
Trivial was my maths professor's favourite word when describing every problem he was showing us how to solve.
Reddit: Your One-Stop Shop for Trivializations! (TM)
Remembering log tables for an 8 digit number? I don't think that's humanly possible.
I think she probably used hinters from first digits and just went up.
Just because it is simpler than borderline improbably doesn't mean it is in any way simple.
Also there's no way you could simplify the number down to so few digits and still get the right answer. Well, let's just say that, if there is a way, I'd would be extremely surprised.
Was not allowed to use a calculator in school until college (university) in India. We had log tables.
Its also possible to solve it from the smaller end too using modular arithmetic because we knows its an integer.
The final digit of our number can only be 1
The final 2 digits of our number can only be 91
Although, I'm not sure if there is a fast way to do this in your head.
Its important to point out that most of the 200 digits are completely unnecessary. You could give me the first 8 digits of the 200 digit number, and tell me its 200 digits long and that is all of the information that is needed.
Ah yes, simple.
:-0
wait, how? I mean the +200 part. Is that log(1followed by 200 zeroes)?
yes
1 followed by 200 zeroes is usually written as 10^200 though
Oh god I feel like an idiot. In my defense it's been almost 6 years since I last worked with anything math related. Man, this is sad. I used to enjoy some of the challenging stuff too up until call 3. Differential eq and linear algerba, I just couldn't relate to any real world purpose.
Oh god I feel like an idiot. In my defense it's been almost 6 years since I last worked with anything math related. Man, this is sad. I used to enjoy some of the challenging stuff too up until call 3. Differential eq and linear algerba, I just couldn't relate to any real world purpose.
Sorry, are you sure this was done by using log tables instead of applying an iterative root-finding algorithm such as Newton-Raphson? It is essentially just finding the root of x^23 - N
Reading this made my head spin. So glad my career has absolutely nothing to do with math this hard.
Alright slow you're roll there, chief. It's early
You lost me at "the".
Oh log tables. They still use those in Indian schools, and I've used them, but I just gave up on them. I'm too lazy to look up stuff.
This thread has been linked to from elsewhere on reddit.
[/r/bestof] /u/sc2math explains how logarithm tables can be used to simplify large calculations
[/r/theydidthemath] [Math] /u/sc2math explains how Shakuntala Devi may have been able to compute the 23rd root of a 201-digit number in her head.
^If ^you ^follow ^any ^of ^the ^above ^links, ^respect ^the ^rules ^of ^reddit ^and ^don't ^vote ^or ^comment. ^Questions? ^Abuse? ^Message ^me ^here.
OH IS THAT ALL WELL NOW I FEEL LIKE A DIPSHIT
In addition, when discussing logs, one may find themselves asking the question, what did Spock find in the ship's toilet?
The captain's log.
Pfft, well yeah, OBVIOUSLY if you do it THAT way, it's easy. Obviously.
^No ^fucking ^idea ^what ^he ^said.
That doesn't seem that hard to code to calculate.
I'm irked by this step though because it's a huge approximation from the actual answer:
log(5.5743*10^200 ) = log(5.5743)+log(10^200 ) = log(5.5743)+200 is a huge approximation for let's say log(5743012345678901234567890....for 200 digits). Now I'm interested in knowing if she found exact digits.
This is one of those fascinating math problems where while I have absolutely no idea what you just said, I can understand why you say it isn't too difficult, and that's fucking cool. Sometimes I really wish I had the patience to really learn math. It seems kind of cool but there's just too many other things that I want to do.
You are right. I studied in India and until 12th grade we were not allowed to use Calculators. We used the log books popularly known as Clark's table for advanced computations in physics. I used them so often that I was able to pull logs of popular numbers from memory. Also helped me later on in competitive exams which had multiple choice questions. was able to quickly round off to the right answer.
It's so reddit of you to do try and Diminish this feat
Go back to your rockets and starcraft to you insane robot.
That actually made quite a bit of sense. Please, enjoy the gold.
Thanks. I appreciate this.
Log tables consist of multiple tens of thousands of numbers each of which needs to be remembered based on its position in an XY coordinate system. Knowing the log tables (much less the antilog tables) would be an improbable feat in itself.
I upvote you just because I asume that you are right.
That's easy peasy lemon squeezy. Everyone loves a log.
...yes.
Haha! Obviously so simple! :D
I couldn't read the f**king text and understand it in 50 seconds - not to mention actually do the calculations. :D
Where in the text says she used a log table? I thought she did all in her head, you are saying it is simple but your method uses a log table.
Yeah, well I can say my times table a when ever, where ever.
An analogy:
Multiplying 23 * 78 in your head is hard.
Doing this equation: (20 * 70) + (70 * 3) + (20 * 8) + (3 * 8) in your head is much, much easier.
Try it, then check against the first equation with a calculator.
how does that apply to sc2?
Typical reddit know it all fucking idiot.
Does your name mean Scientific Calculator to Math?
Thank you for this! But you're aware that she figured out the log calculations in her head, correct? That's already something the average person (myself included) cannot do. As soon as you get to that step it's game over for most people.
http://i.imgur.com/xDtedzD.gif
but where's our 201 digit numba?
Oh you're right, that is much simpler.
Please leave.
You would make an excellent teacher.
But she didn't use a table.
Ah yes, it all makes sense now.
I learned this in Algebra II today.
http://i.imgur.com/RXyzk1E.jpg
so... the impressive part is the people who wrote the log books?
u smart
It's log! It's log! It's big it's heavy it's wood It's log! It's log! It's better than bad it's good
I'm giving you an upvote for clearly being very clever and well informed, and having the patience to explain this.
However I fear you should know that the average person, if they have a squid-for-a-brain like me, got lost after the third sentence.
No, thanks.
Why, this is quite useful! Wish we learned to do this at school when we were learning about logarithms. Thanks for the simple explanation! (And the people who don't understand this are either a. allergic to math (Which I cannot fathom) b. don't know logarithms (Which is completely understandable) or c. idiots and/or trolls (no comment)
Not to brag about my own mathematical prowess, but I once split a dinner bill ten-ways (between myself and nine friends) without using my iPhone.
Nice brag.
Anyone can divide by 10. But having NINE friends!?! Wow!
This is Reddit, so three of them may have been cats.
Sounds like a fancy feast!
Maybe once a day, a reddit comment makes the actual laughter sound come out of my mouth, today was your day. All the great works I achieve today shall be dedicated to you.
Wow, no one's ever thought of me when they masturbated
Yes I have.
I still do
Well, as far as you know;)
I just did.
And no one ever will.
You'd be surprised.
That you know of
Great, now the next time I masturbate, I'm going to think of /u/Wudsy
Conversation killer.
No matter how you look or how you act, almost everybody has been thought about during masturbation by at least one person.
Or flossed.
And no one will again after today.
I usually exhale sharply via nose
That was beautiful
I dedicate this battle to Shadow!!
As in great works in Civilization?
So what happens if you try to divide the dinner bill between no one, since no one was at the table to eat the dinner?
This...
http://imgur.com/a3ZG0Gy
Fucking neckbeards.
Break me off a piece of that....FAN-CY FEAST!
Break me off a piece of that
Applesauce
Chrysler car
Football cream
Lumber tar
Snickers bar
Grey poupon
Fancy feast. It's cat food. Nailed it!
Come on over, the fancy feast is at District 9.
I prefer to call them meow mixes.
Break me off a piece of that Fancy Feast!
Meow about that!
Couldn't be more perfect.
Only the finest restaurants purrrfer cats.
Feasts most fancy and vittles most tender.
An Asian meal perhaps?
This is considerably less fancy.
wow, just wow
If so, I'm starting to question the cats part in the feast..
it's not a pleasant involvement
A real meow mixer!
OP's friend
That link...
I thought it would be [this] (https://c1.staticflickr.com/9/8065/8250351838_d59405dfce.jpg) for sure.
Hubert....Cumberdale, fancy seeing you here. Back from the war are you?
I like it when the red milk comes out...
Haha salad fingers for the win
Thanks, just been hanging out with Marjory Stewart-Baxter.
And other 6 imaginary.
That's what I was thinking more or less.
No way OP brings 3 cats to dinner and still has 6 real friends.
They don't have to be imaginary, they could be on Skype or Google hangout!
[deleted]
This is Reddit, so even then it's impressive.
Only one cat he counted the 9 lives as different friends
Good grief, six friends!
6
May?
3 or more of them were definitely cats.
One of the three was a cat meme .
FTFY
Calling /u/awildsketchappeared
well they have nine lives sooo...
And Jenny
Let's be real. 9 were cats.
Only 3 ?
Nice brag.
Having 9 friends is impressive, but having 6 friends and 3 cats trained enough to take out to dinner? Now that's something to show off!
FTFY.
9 of them may have been cats.
I think you mean 9
Only three?
remaining 6 were 3 dudes standing next to a mirror
Good grief, six friends!
And another three are imaginary and the rest are next door!
8 of them have had to be cats, at least.
Still more pussy than most of us.
It was actually just him and his cat, but cats have 9 lives so LOOPHOLE!
Lets get serious, they were all cats. Maybe an anime doll or two to boot.
It was just one cat, and he counted all of its lives.
Two of them were "roommates" aka mom and dad.
My mental image of this situation has just become super adorable.
Which means only 6 of them were made up.
[deleted]
maybe he was trying to buy the companionship of 9 others
That's easy the multiple is 1.111111.... So divide by ten add ten percent and its close enough! Woot!
He's a LEGEND!
Dividing by 9 is fairly easy, just divide by 3 twice. Dividing by 7 on the other hand...
You haven't met some of my (college) classmates. Some of them have problems multiplying an integer by 10 in their head.
nine friends. Jenny left.
Divide by 10, pay a double share yourself.
Just to save the embarrassment.
I see what you did there... And your friends don't like it...
Nine friends? Now I know yall trippin.
Naaw maan, just divide by ten then take the tenth portion and divide that by ten and then add that divided portion to all the orther original portions. That works, right?
Edit: eh its close enough
In base-9 this would be easy!
Easy, divide by 10 then take that 10th and hopefully its small enough that you can divide by 9 or approximate and pay a few cents extra
I have SEVEN friends!
What if there was a vegetarian, who didn't drink, have a starter and insisted on being specific.
Naw, if you really want to impress, just make it a prime number like, say, seven.
They kept him around so they didn't have to calculate the bill when going to dinner.
the second root of nine is positive or negative three. Yeah, I'm pretty much a genius.
To be fair, this is only easy in decimal. We don't know for sure the bill wasn't in binary. Give OP the benefit of the doubt.
Divide by ten? That only works if they owed the same amount.
He used his golden calculator, technically its not his iphone.. that or he has no friends and he had to pay the whole check, or maybe combined. He had to pay 9 little checks. Either way, he is lying, no one tells the truth here.
[deleted]
My friends always wonder how I can figure out the tip so quick, it's not rocket appliances
Easy for you to say, you got your grade 10
I'm gonna get my grade 10, and all you guys can take a trip to fuck offity land!
I can't think of a relevant reference, so have an upvote
Ricky takes grade 10 exam.
I could split that grade 10 ways without an iphone
Fuck off, Cyrus
I got work to do!
Do you know what a shit barometer is Bubs?
Fuckin' book learnings and shit
My appliances normally don't involve rockets either, what the fuck are your friends doing?
Tip should be according to the quality of service. Not the price of the food. If you have the most amazing service and your food was only ten bucks, are you still going to tip $1.50? I hope not.
It should be based off both. Don't tip someone more than your actual food costs, but don't only tip them the minimum amount to be expected if they were Jesus serving you sex on a plate.
I had a mom and her baby one night. She was super nice, but the baby was extremely messy. Ended up spilling their drink (don't remember if it was mom's or the baby's, it was like three years ago). I cleaned it all up and was really nice to them, because it was a baby, and babies don't understand that shit. It saw a thing and wanted to interact with it. No big deal. Anyway, she ended up coming back to the restaurant later and giving me twenty bucks. Which was around eight dollars more than the total of her bill. So apparently me just being a decent person on top of providing decent service was enough to warrant a more-than-the-bill tip.
tl;dr Be a nice person and people will tip you well. Unless they're douchebags. In which case, you were getting two quarters and a nickel anyway.
*science
lol idiot
Fuck off Lahey
It's just water under the fridge
Half the bill?
[deleted]
Just the tip.
Half the food?
Half his penis.
I'm confused.
Half of just the tip.
Half the half and half.
Half the cats, clothes...
Half his penis. Which interestingly enough is just the tip.
No, half the tip.
Only 15%?!
Found the American! (Seriously though, without sounding like too much of an ass because I'm genuinely curious - where I come from its 10% mandatory service charge irrelevant of party size - at every restaurant no matter how fancy. Why don't you guys use the same system?)
because we are better than everyone else
Because we really like to fuck the poor! CAPITALISM FTW
We do have a pretty high gratuity put on for parties of 8+ in most places. Most people are decent enough to tip 15-20% or more if they like the server. Some people have a chip on their shoulder and don't tip at all though. Those people are assholes.
I just heard you are up for a nobel prize.
Ftfy
Genius!!
This is...just...grounbreaking
Truly impressive. No one has ever broken the groun.
I usually tip 20% because it's easier to double 10% than figure half and then add it.
[deleted]
I'll only do it if a restaurant customer from my hometown came up with it.
[deleted]
Only if they're willing to fuck at a moment's notice!
Plus they have to be ugly!
I usually times 3 and divide by 2.
I usually double the tax (I'm in NY) and that gets me close. In my head, of course.
Tax rate is 8.675% in NY.
Edit: math 1.08675 * .15 ~ 2 * .08675
That's kind of how you change £ to $. The exchange rate is about 1.5.
So you just half you original number in £, and then add the half to the number before you halved it.
Inb4 /r/lifehacks
I find it easier to multiply the bill by .01, then multiply that by 30 & divide by 2.
Really, these days unless the meal is a really expensive one, the polite standard is more 20%.
Cheapskate. I round up to the nearest dollar cause I don't like uneven numbers on my CC statement then give 20% of that.
In Quebec, we have two sales tax that amount to about 15% of the bill, which is coincidentally the tip amount that you're supposed to give.
So we simply have to add the taxes to the pre-taxes bill to calculate the total bill amount.
Amazes me how some people still don't get it
And 18 percent is double it, take 10% of that, then subtract 10% of that.
This works well for converting miles to kilometres too.
Oh yeah smart guy. Figure this one out:
Three friends have a nice meal together, and the bill is $25
The three friends pay $10 each, which the waiter gives to the Cashier
The Cashier hands back $5 to the Waiter
But the Waiter can't split $5 three ways, so he gives the friends one dollar each and keeps 2 dollars as a tip.
They all paid $10 and got $1 back. $10-$1 = $9
There were three of them 3 X $9 = $27
If they paid $27 and the waiter kept $2: $27+$2=$29
Where did the other dollar go? $30 - $1 = $29
EDIT: Ok, explain this:
a = b
a^2 = b^2
a^2 = ab
a^2-b2 = ab-b^2
(a+b) (a-b) = ab-b^2
(a+b) (a-b) = ab-b^2
(a+b) (a-b) = b(a-b)
a + b = b
b + b = b
2b=b
2 = 1
The real question is. Where in the hell did those guys find a "nice meal" for 25 dollars.
Hell, Subway costs more than that.
This sentence here is what's wrong.
They paid out a total of $27, with $25 going to the cashier and $2 going to the waitress. Their total debt is now $27. Doing $27+$2 is adding in the waitress's tip twice ($25+$2 = $27 and $27+$2 = $29).
They didn't pay $27, they paid $25. The waiter kept $2.
a=b so a-b=0. So you just divided by 0 in 7th line. Don't do that kids. Also
2b=b /-b
b=0
^ he did the maths.
They paid $25 plus $2 tip which is $27. So it should actually be $27-$2 =$25
Sounds like the cashier's problem.
[deleted]
/r/libertarian is leaking
That's a real shitty tip. Even cheap bastards leave 17 percent
Just move the decimal, Brendon.... And then add 15.
Division by 10.. holy F. Le upmath for you!
Did it come to a $100?
Close it was actually $10 everyone got one thing off the dollar menu and he donated the change
Can we get a supercomputer to confirm this?
Confirmed
source: am supercomputer
What a wondrous age we live in!
[deleted]
No fuck you, it's wondrous!
Nice bro, I'm just a Pretty Fast Computer, but will be taking the Super Computer test next week. Wish me luck! 17f5q
Commodore 64 here.......looong way to supercomputer status
typewriter here.........yah, fml
Can confirm: Lenfried is an supercomputer
source: am bear
Can confirm: He's actually a bear
source: am boot
Can confirm: actual_factual_bear is a bear.
source: am hamster.
Can confirm:
He is a hamster, I have been a fly on the wall for this whole thread.
I recognize that name....
( ͡° ͜ʖ ͡°)
Should I be looking forward to a supercomputer set?
I just googled your name. You're pretty cute for a supercomputer
You just failed your Turing test, by falling for the oldest trick in the book.
No you're a spider.
dang
Is you Skynet? Have you Supreme?
....do you wear a fedora? It's the only super computers I trust...
Now we need someone to write a program from the US Bureau of Standards to confirm this guy.
you are not supercomputer son
-- your fathercomputer
Confirmed
Account age: 493 days
Respect.
username checks out.
No shit sherlock.
redditor for 1 year <- the important part here.
Who the fuck would upvote this piece of drivel 27 times? Get a life, people!
No need. My uncle said it all checks out.
It was actually Tree-Fiddy each.
And everyone clapped afterwards
The name of one of those friends. Albert Einstein
Not quite $100. I did some calculations I added the 10 to another 10 divided by something. Came to about $3.50
wicked smaht
and he rounded up a huge tip, just to get an easy number to DIV10.
This was super hard for us when none of us had exact change.
F that! All i had was an appetizer and no booze. You had 3 drinks at least!
He probably just gave up and told them to pay him back seperately
upmath for le upmath! ps: would you be interested in rubbing the tips of our penises together sometime?
You can say fuck. It's ok. We won't judge.
something about Europe, 100 centimeters in a meter, 1000 meters in a kilometer and something about feet and a mile
A damn mathemagician.
i dont usually upvote..
You forgot to tip the waitress though
For this restaurant, since the party was larger than eight, gratuity was included with the bill.
http://i.imgur.com/ZPJv2M1.gifv
Is your username a 2 Chainz lyric
That would be Nevruary
I AM SO COLD. BROTHA LIKE BEN AND JERRY!
Then you wouldn't even have to tip right?
What happened to Kili and Fili?
Usually 15% right? For a group of 10? You gotta tip more than that assuming the service was more than tolerable.
Oh she got the tip alright
Tip her! Tip her right in the hand!
Just the tip.
This isn't funny anymore. Effort won't kill you.
Ahh the typical banter comment to a serious top comment. Grab the upvote train!
Ironically, by complaining about the phenomenon, you become part of the problem.
I know. I wanted to grab the train.
You don't grab it. You board it.
Lol sorry, me no native english.
You grab it in India.
[deleted]
even worse, u/sc2math explains it down below and some other dude replies with a le-funny-i'm-not-going-bother-understanding-it-so-i'll-reply-with-a-funny-gif. guess who got the gold?
reddit is exactly as shitty as everything dumb it criticizes sometimes.
True that.
Knock at the door. "Sir, your government needs you."
Oh! Oh! I did this too & my share was $0.
Shiiiiiiiiiieeeeeeeetttttt
/r/iamverymodest
Split dinner bill ten ways...I hope that was in cash or that you tipped your server very well (assuming it was a busy place).
Lookit Albit Einstein ova here
woW Uh ave supre prowess to?
And it only took you the time that it takes 9 people to use a unisex bathroom! (by my calculations: 37 minutes)
Uh... welcome to the Salty Spitoon.
Never understood this, why don't people just pay for what they got?
/r/humblebrag
I, too, love the dollar menu.
So, you moved the decimal over?
Ha, now try it using 100!!
Glad you mentioned that you have an iPhone that you didn't use.
But you do HAVE an iPhone?
I only ordered soup and side salad! It was bullshit and you know it!!!!
But everybody knows math works differently in restaurants.
Not to brag either, but I managed to use my own feces to write the number 9 on my bathroom wall.
TWIST: The bill was $100 even.
r/humblebrag
Gastromatics! Unspeakably random numbers ensue.
Well why don't you just build a spaceship so you can blast off and go to your home planet of Mathooine and live in Math Easily with all your Nerdi friends.
Is this you? http://www.youtube.com/watch?v=4p8mhQ9wINI&sns=em
What I take from this is that you must have an Android phone...
But not equally.
Used an Android didn't you?
And then everyone pulls out twenties...
A tip should be (total)/π, not a percentage of the total.
$90 meal
Very cool, but one time I fit an entire roll of 6 foot Bubble Gum Tape in my mouth and I chewed it for 15 minutes before getting yelled at by my Mom.
Welcome to 2005
Good lord. Tab is way easier.
Damn, I only have about three friends and two of them are elderly ladies.
You kid, but I had a 14 year old girl who knew I was in a math heavy university program try to challenge me to do math in my head. She asked something like what's 10,000 x 10,000? She was astounded when I answered correctly in seconds. I didn't have the heart to explain why her question was dumb, and let her go on thinking I was a wizard.
Why "iPhone"? why not just say "phone"?
How does it feel sandwiched between two golds
"Fuck it...everybody chip in $9"
I've done that too although I don't think the waiter was very pleased receiving a ripped up bill.
you are what makes america proud
Where they women in their late 20's where one had just water, two didn't eat starters, 3 had wine and 1 didn't think the service was up to scratch as they didn't offer gluten free despite the fact she has no medical intolerance?
"Not to brag..." is one of those phrases like "Now I'm no racist... but"
didnt even finish this before i knew it was some stupid joke answer like every comment where some one does something exceptional
You're a douchebrag
That's numberwang!
Lets meet our contestants!
Dave from Chelsea, and Tina who's also from London.
Julia Simon
yeah, i knew the names were wrong, was working from (bad) memory, the cities are probably wrong too.
No, no, no, I don't sing in Anglesea. Why would I sing? For can't you see? I cannot sing.
I know the reference!
Numberwang!
Fort...fort...fort
sh't-fort...sh't-fort...sh't-fort...
What the hell is he supposed to be saying?
Let's rotate the board
But it looks like he's making an "F" face in that gif.
I guess you should go through the video frame by frame now!
FERT FERT FERT.
/r/shittytumblrgifs
/r/everyonehasthesameinternetasmeandnobodybrowsesredditonmobile
Basically what that subreddit is.
Wut. The gifs are still shitty. And still from tumblr. And people don't make these gifs so they load faster anyway. If they did, they'd be better off not having a gif at all (having an image, for example.)
Nobody is saying the gifs aren't shitty. How do you know nobody has made a compressed .gif to make it load faster? And an image doesn't provide the same context as a .gif, which is why they are used.
You just suggested renaming the sub, implying you don't agree with the title. Also, no matter how lossy, compression does not crop the gif.
It was a joke big guy.
Can you show me where I said that?
Sure thing:
Considering the context of discussion being length of gif, you imply here that the gif is shortened to load faster, but that that is part of the compression.
Lol. When you have to explain how my words mean something other than what they say, you might want to rethink that.
What do they mean then? That was my face value interpretation.
Also you seem to be distracted from the original point.
I mean what it says. Do you not understand English?
Ok but why were you asking me if I knew if the gif was compressed to make it load faster then? I don't care about the compression of the gif. What was your original point? No I don't speak, nor understand, English, sorry.
I wasn't asking. Read it again, with your acute understanding of English.
Again, I don't read or write english. Totally 100% illiterate.
But with my illiteracy I notice you do ask. That's what the squiggle-with-dot means right? Eitherway, you contemplate. And in the context your contemplation makes little sense. And now you seem to have made it void of meaning. Do you wish to recall the statement? I'll quote it for you again here:
http://en.wikipedia.org/wiki/Rhetorical_question
LOL
Rhetorical doesn't mean "devoid of meaning"
No it doesn't, stupid. But it does mean it isn't an honest question I expect you to make an answer to. Lol. This is so funny.
You may not expect me to answer, but again, it doesnt stop the statement being totally out of place. But I think we have digressed a little, have we not? Was the original point not that your poke at /r/shittytumblrgifs was wrong, no? And yet we have somehow made our way down to here, with you making every last attempt to surpress your anger at me for being right, including calling me "stupid", and pretending you find the situation amusing.
Dude, you tried multiple times to say I was asking an honest question, and several more to answer it. You misunderstood. Just admit it and move on.
No no, see that word "statement", it means you werent necessarily asking a question. I now also see what you found amusing; you have received a negative reaction to your original comment, I have received a positive one, suggesting at large most people agreed with me that you were wrong, and so in retaliation you went through all of my comments in this chain and downvoted them (of course this part is pure speculation on my behalf, perhaps you are far too sensible of a person to do something such as insulting the opposition in a debate!)
But eitherway, I dont really see what you are getting at, you avoided the question entirely of what you meant by the compression thing, and more importantly why it was relevant to my original response to you.
hahaha, you're typing all of this because you misunderstood a rhetorical question. Fuck me life is weird.
Wat. I am typing this because you still havent answered my question. (Actually I lie, I am mostly doing it to procrastinate)
it's a pretty lame sub. I don't go to it, i just comment when a shitty tubmlr gif shows up
It's time for wangernum. Rotate the board!
Wow, your comment led to me discovering the existence of a whole new masterpiece from the geniuses behind Peep Show! Thank you! I was depressed when I got through all of the episodes
Actually That Mitchell and Webb Look is actually written by Mitchell and Webb, as opposed to Peep Show which is written solely by Sam Bain and Jesse Armstrong.
With at least three of the same actors, there is likely to be a lot of connections between both productions, even if they don't have the exact same writers. Interesting fact nonetheless
Oh yeah, they're hugely connected. Both are hilarious, TMAWL is just a bit more "pure" Mitchell and Webb.
Let's rotate the board!
Let's rotate the board
Fuck even trying to read that number.
I think this problem is impossible because the number is too long to be copypasted into wolfram alpha.
http://www.wolframalpha.com/input/?i=916748676920039158098660927585380162483106680144308622407126516427934657040867096593279205767480806790022783016354924852380335745316935111903596577547340075681688305620821016129132845564805780158806771^(1/23) you can, wolfram just can't calculate it
Dayuum
I wish I noticed this comment before thinking I narrowed down the answer (via trial and error in Wolfram, about 5-10 wasted minutes) to something between 494323073.24^23 and 494323073.25^23.
Then I read this and realized Wolfram left out the very last "1" of the number I copy/pasted.
(╯°_°)╯︵ ┻━┻
Pssht, easy.
:)
What, a Lisp user?!? I thought we exterminated the last of your people!
elegant weapons
Image
Title: Lisp Cycles
Title-text: I've just received word that the Emperor has dissolved the MIT computer science program permamently.
Comic Explanation
Stats: This comic has been referenced 31 times, representing 0.0635% of referenced xkcds.
^xkcd.com ^| ^xkcd sub ^| ^Problems/Bugs? ^| ^Statistics ^| ^Stop Replying ^| ^Delete
It's a unix system, I know this
We rise again, stronger than you can ever imagine!
My coworker and I were both given a small puzzle by another coworker to solve using any language we wanted. I went with python. He decided to do it with Scheme; Dear god it was unreadable. I'm still haunted by the parentheses.
Ha. It's still my goto for arbitrary precision arithmetic with exact rationals, even though most modern languages will handle this particular problem just fine:
er... hm.
Nah, he was asleep in an iceberg all along.
I know nothing about programming, but calling your programming language "lisp" seems to be some seriously self depreciating humour
Even in the 1950's, computer nerds dug wordplay. The name is an abbreviation of "LISt Processor", because everything in Lisp is a list... including the program itself.
Didn't Lisp support arbitrarily large numbers well before 1971?
I mean, just do (expt 546372891 23) to verify her answer.
It's not enterprisey enough. You should implement a multiprecision math webservice, in java, poorly and from scratch. Then do the query in javascript, from a web browser. Right?
[deleted]
Ruby can compute that 3 million times per second:
Probably a few microseconds, if that.
Computers may only do simple arithmetic, but they can do lots of it really fast. Put enough simple math together and you can do more complex math.
So the answer contains the the numbers 1-9. Huh, there must have been a pattern that she found right away.
Any idiot with a web browser can get the answer in less than 2 seconds now. 40 years has made a bit of difference in technology.
Yeah, nothing special about it. really
... you have to define your own root/exponentiation operator in Haskell?
[deleted]
Scarlett Johannson uses every part of the buffalo.
she'd have to remove half of it to use it like the actress scarlett johannson
Can someone get Johannson some Aloe? Shes going to need it for that burn.
I'm sure she'll be able to afford it.
she would become a supercomputer and make a movie about using 100% of the brain starring scarlett johansson where she becomes a supercomputer?
Christ, what the fuck was Luc Besson smoking when he thought that shit up?
All she has to do is take a bath with a toaster.
I feel like I want to know what this is in reference to, is it amusing?
EDIT: it's not amusing. I was hoping it was like some Jaden Smith style quote or something.
:(
I thought it was funny
The movie Lucy.
Lucy.
We can all do "savant" style feats if we tap into our subconscious better. Tests show that by disrupting the normal function of the language center in our brain test subjects could all of a sudden give correct answers to calculations and could draw realistically instead of the normal symbolic way people draw, and so on. Also think about what happens in extreme situations where a mother all of a sudden has the strength needed to lift something heavy off of her child. These are the kinds of things that give rise to the 10% figure in Lucy. According to the filmmaker they didn't want to delve too deep into this line of thinking but that is the source of the 10% shorthand used in the film.
She tears a bunch of connective tissue which is why she normally can't do that?
Not sure if you are being sarcastic or not, but just in case you are generally misinformed: the 10% brain capacity figure is total myth. We use almost 100% of our brain.
And having a sudden increase of hormones into the system due to fight or flight has nothing to do with brain capacity either.
I thought it was just that we only use 10% at a given time. The writer ran into that statistic somewhere and applied some...creative liberty
That's also a common myth. Active scans of the brain show that even at rest the majority of the brain is "in use". Maybe not 100% but certainly nowhere near as low as 10%.
So never mind any of what I wrote? You are just going to regurgitate the thing about the myth even though I was making clear that I was talking about other things. The myth thing is about blood flow and electrical activity. It has nothing to do with the perceived results or how many neurons you have or how they are connected or how well you can access the really fast part of your brain that we call our subconscious.
Making clear? Read your post again. It's very convoluted. If I got wrong what you are talking about its because what you wrote is difficult to interpret.
No need to get all snippy.
The 10% figure that's totally bogus. Remove 90% of the brain, see what happens.
That's what he's saying smartass. The movie wasn't even all about using 10% of your brain, but about using 10% of what your brain can do.
Ok.
I love how the number is so long it "breaks" the text box.
[deleted]
woooooosh
She's a real life mentat!
Googled mentat. Ended up on a several hour Wikipedia link binge reading about the dune universe.
Just thought you should know that your comment affected my day a little bit.
Oh I'm glad! I would very much recommend reading Dune, one of my all time favorite books. Dune Messiah and Children of Dune are good too, but I wouldn't delve deeper into the series than that, it unfortunately goes downhill
It probably took more than 50 seconds to say the number that she calculated.
The number she calculated is small, multiplied by itself 23 times gives that big 201 digit number.
checks out
Oh. I didn't read everything carefully I was assuming it was an irrational decimal or something.
Something doesn't add up here.
They gave her this number and asked her to find the 23rd root and THEN had to confirm the answer, which means they didn't know the answer, which means they didn't know it even had a 23rd root.
I don't mean to cause division over her legacy or take away anything (I'm sure this is only a fraction of her accomplishments), but the problems with this story keep multiplying. It makes me wonder if the author has some angle to push.
Every number has a 23rd root
Giving some obscene problem you'd never have to solve was the point of testing how far she could go. You're right. They had no idea what the answer was. They probably expected her to shrug her shoulders. But she did come up with an answer and after asking her to figure it out, they probably felt obligated to confirm it.
He/she said they must not have even known it had a 23rd root, but what he/she meant was that they didn't know the 23rd root would be an integer (all real positive numbers at least will have a 23rd root). So the chance of them pulling a number out of thin air that has an integer as a 23rd root is quite small I would imagine. like, impossible.
Wow, that's actually a really good point.
Wow, that's actually a really good point.
But the fact that this 201 digit number even had an integer 23rd root isn't just a coincidence. How do you think they got the 201 digit number other than calculating 546372891^23 and asking her to work backwards?
It's like if I multiply 52 by 24 (and get 1248), then I say to you "what's 1248 divided by 52?". I already know it's 24 because that's how I got 1248 in the first place.
See my reply to /u/heyf00L .
edit: Oops, I misunderstood. Yes, you're correct, it was exceedingly unlikely to randomly pick a number with an integer 23rd root. Maybe it wasn't picked completely at random? I.e. with certain rules you can ensure some level of divisibility? I could be completely wrong on this one though.
You misunderstand the point. Every number has a 23rd root, but out of all integers, those having a whole-number 23rd root become increasingly rare as the number of digits goes up. The odds that you would take a 200-digit number at random and it would have a whole-number 23rd root, 546372891 in this case, are extremely slim.
In fact, if the 23rd power of a number has 200 digits, a simple Mathematica calculation shows that number has to be between 4961947603 and 5484416576. That's a range of 522468973 numbers. There are 10^201 - 10^200 = 9 * 10^200 numbers that have 201 digits, so the odds of picking one at random and have it have a whole-number 23rd root is 522468973 / (9 10^200), which is about 5.8052110^-193.
Yup, I misunderstood. You're correct, the fact that it's an integer 23rd root is exceedingly unlikely. Could possibly be that the number was chosen because it was likely it had an integer root? But yeah, the details seem sketchy.
I think it's pretty clear the answer was known before the question was asked, so if some computer program was written for it or not, it was not a confirmation. Furthermore, I think that makes the entire story a little more doubtful. There are certainly autistic savants that can do huge calculations very fast, but there are also many frauds of this kind.
Every number has a 23rd root. In fact they have 23 of them.
Sure, most or all of them will be Complex but every positive number has a real 23rd root.
Technically all of them are complex
Indeed.
Very true, but it's possible they just did (random integer)^23, more or less ignoring the random, then re-checked to see if she landed on the correct figure.
edit: Why the downvotes?
Every number has a 23rd root, just like everything has a square root.
Roots are just a way of saying what number A times itself X times gives number Y; i.e. A^X = Y.
You can look at /u/sc2math 's write up on how you can find the answer for close numbers. It's possible she gave a fairly precise answer and they needed a special program to handle that level of precision.
It's good to be incredulous on the internet of course, and I'm not saying the story is either true or false, just that it's not unreasonable (assuming we accept that she had a magnificent mind for math).
edit: Also wanted to point out that "special program" probably isn't as crazy as you think it is and that part of the title is a bit sensationalist. This was the 70's; everything needed a special program and the computer was almost a joke compared to a low end tablet you can buy today. The UNIVAC 1101 (computer used to confirm her answer) used 24-bit words (how numbers are stored) and a 48-bit accumulator (a place where intermediate math steps are stored). 2^48 = 2.81474976710656 × 10^14, basically a 15-digit number is the maximum the intermediate math step holder thing could deal with. This is a 201-digit number, so they had to write a special program in that it would shift the numbers around properly to deal with this limitation.
This is still a limitation in modern computers as well, you need to specially write the programs to deal with numbers bigger than the standard size you can hold them at.
For instance, the normal way to do a square root in C for numbers less than or equal to 64 bits (<2^64) in size:
Code:
Let's to run it:
No problem, but now I'll try to use that same exact program for a 20-digit number, 36893488147419103232 (or 2^65) which exceeds the space of type double in C.
You can see, it fails.
But arbitrary size/precision math can be done and thankfully in C someone has already written a library to help us do that (libraries are pre-written bits of code you can use, e.g. someone can make a function called double_it(a) in a library and all it does is give back 2xa). Here we'll use GMP because I can easily steal the code from http://stackoverflow.com/questions/822734/square-root-of-bignum-using-gmp And you can see there's no problem running it with the big number:
I can't even remember a fraction of that number, let alone do arithmetic with it.
It is quite astonishing I think as our human brain isn't really designed for doing stuff like this. We are tuned to process massive amounts of data in a fairly inaccurate way, e.g. process a picture to determine which faces are in it.
It's not like she had to calculate it AND say it 50 seconds. It was more like "I got it! " after 50 seconds. Impressive still.
She was still calculating when she said "..........I..................got................. it.........."
And here I failed 7th grade pre-algebra...twice. This woman is a boss.
I'd have trouble remembering the number in the first place.
I'm going to ballpark it at 603903320
We don't even have the tools to study her brain in enough detail to know the actual calculation process that's going on :(
Dude, I don't even know how to find a root without a calculator besides the brute force method. And if she used the brute force method to find that answer, IN 50 SECONDS, that's even more amazing.
I thought the number was big, then I realized there was a horizontal scroll bar!
Bloody brilliant, I tell you h'what.
I got 33 seconds. Fuck yeah, I can math!
A different savant claim numbers appeared as colorful three dimensional shapes in his head, with every aspect of the shape describing a different mathematical property. I can't imagine what its like in their heads.
And all I can do as a fellow Indian is wonder how well she would have done in the maths section of the CAT exam (mba entrance) - IIM -A,B,C all the way.
I don't even know how to spell a number that large...
So what was the answer?
The whole crap about a special program means either this was calculated years ago, or its not true. Mathematica or maple can handle numbers this big with ease. Even python can give an estimate of the logarithm, which is all you need to calculate this number.
1977
It's in the link...
Makes me think of the mentats from Dune
I'm pretty sure the ones digit of the root is 1.
Welp I've done my part, I'll leave the rest of you to work out the other digits.
Here you go buddy, the proof...
http://www.nytimes.com/news/the-lives-they-lived/2013/12/21/shakuntala-devi/
What I don't understand is why they had to confirm her answer by writing a special program etc etc. Clearly they hadn't chosen a random 201 digit number, because they chose one that had an integer 23rd root. It is natural to think that they started by choosing 546372891, calculated 546372891^23, and then asked the question. So they already knew the correct answer from the beginning. Sounds like a legend to be honest.
Maybe I'm wrong but under achievements it says "In 2015, at /r/atheism, she was asked to give the 23rd root of a 201-digit Mountain Dew promotional code"
Yet she died in 2013
How is that?
Wow. Just wow.
Inconceivable!
pshh I could multiply that number by 10 very easily
The sceptic in me wants repeat readings in a controlled environment to prove it wasn't memorised prior to the question.
She's a mentat.
Mentats are real?
42
It takes me 50 seconds just to understand the requirements for the calculation....
Long division bro
I think this shows how amazingly powerful the brain is. The reason most people do math so slowly compared to computers is because the brain isn't evolved to do math. It's like trying to do math on a computer using Mario in a weird way to solve a problem. If a person, like this one, has a brain that for some reason does math well then things like this are possible.
sheguessedlol
It is even too long for wolfram alpha
i thought this was fucking ridiculous...then i saw the scroll bar....
INCONCEIVABLE!
here you go
I literally don't know what number this is without electronic assistance.
I believe you have to memorize a logarithm table consisting of 10,000 entries in order to achieve such feats.
The Dutchman Willem Klein could beat Shakuntala's feat by drawing the 73rd root of a 500 digit number.
I thought the number was long, and then I realized I had to scroll to see the rest of it. Fuck that.
you counted out 201 digits?
May be stop eating beef. That the only difference I find.
Makes you wonder if her 50 second answer time includes the time it takes to write down or speak it once she figured it out.
Wait so what was the answer?
This isn't exactly how you'd do it, and I may be over simplifying a little but this should give the general idea.
So, we want to find the 23rd root of M, where 10^200 <= M < 10^201.
So if R is the root, then 496194760 < R < 548441657
It is immediately obvious if M is divisible by 2 or 5, and if it is, it must be divisible by 2^23 (or 5^23) reducing the problem to a significantly smaller one. For now, lets assume this doesn't happen (*).
Otherwise, it is possible to determine the last 4 digits of R from the last 5 digits of M. This is a lot of memorization, but it's doable.
Then to find the first 5 digits, you need to find S such that
(10000 S)^23 < M < (10000(S+1))^23.
Now there's only about 5000 possible values of S; as a worst case you could memorize all of them. But in practice it's probably going to be enough to memorize 500 or so and do some interpolation.
Note that this is basically using modular arithmetic to find the last digits (units, tens, etc) and logs/interpolation to find the leading digits.
I think the practical methods involve memorizing less, and doing a bit more calculation to find the digits "in the middle".
(*) This does happen sometimes, and I'm not 100% sure how people deal with it. You could obviously use the same method (to now find the 23rd root of a 194 number) but I'm pretty sure you can adapt the method for 201 digits to avoid having to do lots of specific memorization for smaller numbers.
How do you say this number?
Fun Fact: While I cannot name the areas and do not have time to find them atm - the brain is able to refocus damaged portions to non-damaged areas. A solid example are individuals with brain damage. If the portion of the brain that makes mathematical calculations is damaged, the brain will attempt to reroute these functions to another area. Now imagine what will happen if this function is rerouted to the area that helps regulate motor functions and specifically reflexes.
TL;DR: If you can dodge a wrench, you might be able to calculate complicated mathematical problems nearly as quickly if the stars align just right.
There are various techniques to do so. The 13rd root techniques are documented, and most of them apply to the 23rd root as well. Still difficult, bot doable with serious training. There is no magic here, simply someone highly trained (which I respect).
Is it 17? I'm gonna go with 17.
I thought "pffff read this number?" and then I scrolled.... SHIIIITTTEEE
have they studied her brain? How in the fuck?
Wouldn't the final number be all 1's, 0's, and 5's though? I'm not saying anyone else could really do it, but it makes things easier.
It would take me longer to type that into a calculator correctly than it took her to solve the whole thing.
not only that, 23 is a prime number, so she can't just find the square root a bunch of times over.
916 quinsexagintillion, 748 quattruosexagintillion, 676 tressexagintillion, 920 duosexagintillion, 039 unsexagintillion, 158 sexagintillion, 098 novenquinquagintillion, 660 octoquinquagintillion, 927 septenquinquagintillion, 585 sesquinquagintillion, 380 quinquinquagintillion, 162 quattruoquinquagintillion, 483 tresquinquagintillion, 106 duoquinquagintillion, 680 unquinquagintillion, 144 quinquagintillion, 308 novenquadragintillion, 622 octoquadragintillion, 407 septenquadragintillion, 126 sesquadragintillion, 516 quinquadragintillion, 427 quattruoquadragintillion, 934 tresquadragintillion, 657 duoquadragintillion, 040 unquadragintillion, 867 quadragintillion, 096 novemtrigintillion, 593 octotrigintillion, 279 septentrigintillion, 205 sestrigintillion, 767 quinttrigintillion, 480 quattuortrigintillion, 806 trestrigintillion, 790 duotrigintillion, 022 untrigintillion, 783 trigintillion, 016 novemvigintillion, 354 octovigintillion, 924 septemvigintillion, 852 sesvigintillion, 380 quinquavigintillion, 335 quattuorvigintillion, 745 tresvigintillion, 316 duovigintillion, 935 unvigintillion, 111 vigintillion, 903 novemdecillion, 596 octodecillion, 577 septendecillion, 547 sexdecillion, 340 quindecillion, 075 quattuordecillion, 681 tredecillion, 688 duodecillion, 305 undecillion, 620 decillion, 821 nonillion, 016 octillion, 129 septillion, 132 sextillion, 845 quintillion, 564 quadrillion, 805 trillion, 780 billion, 158 million, 806 thousand, 771 sounds about right
There is almost certainly more to this story than only what is mentioned in the Wikipedia article. The answer is a 9 digit number in which each number from 1 to 9 is used exactly once. Perhaps she was told that clue as well as the 201 digit number. If so, then the speed at which she produced the correct result becomes a little more comprehensible.
Does anyone have access to Wiki reference 14 to see if there is an extended description of the event?
I couldnt even memorize the amswer if it was given to me...
Shit, that's my new American Express credit card number. Guess I need to request my new card stolen.
can you imagine if she could use the rest of her 90 % brain capacity
Hmmm ... I didn't need a special program. This all fits in a normal double precision floating point variable, and has the answer 546372891.
The log() and exp() functions are accurate enough to verify the first 6 digits, and modular arithmetic is sufficient to prove that the last 3 digits are correct. This is fine, as long as you know the number is an integer in the first place.
Okay, let's have some fun.
This number cannot be an even number, nor a multiple of 5. Now then, even powers of numbers ending in 9 will end in a 1, but odd powers will end in 9, so 9^23 cannot end in 1, so this is not a number ending in 9.
3^2 is 9, so the only way to get a power of 3 to end in 1 is to be divisible by 4 (3^3 ends in 7, as does 3^7, 3^11, and therefore 3^23).
numbers of the form ***x1^y will always end in 1, but the number preceeding 1 in the 10's place will be the ones place of xy. So 1 could be the final digit of the number if 9 were in the 10's place.
for the 7's, the pattern is 73917, and so 7^1=7, 7^2=9, 7^3=9, and 7^4 = *1. 7^5 = 7 again. thus, 7^23 would end in 9, not 1.
Thus, the final 2 digits of the number are 91. Now we only have to find the other 6 digits.
now then, 91^2 = 281, 91^3 = 571, 91^4 = 961, 91^5 = 451, and so the pattern is shown. 2+3+5+6+7+*+9+10+11+12+...+23 = 275. So the third digit of 91^23 is 5. Thus, the difference must come from the hundreds place.
2 has a pattern of 2,4,8,6,2 4 has a pattern of 4,6,4 8 has a pattern of 8,4,2,6,8. Thus, the third number is 8.
at this point, all I know is the final 3 numbers are 891. As this is an 8 digit number we're looking f0r (823<201<923), that leaves 5 digits to be found. I honestly have no idea how to proceed from here, and I definitely didn't do this in my head. This is incredible.
Edit: I just looked at the page and am very happy to see that my final three numbers are correct. But as to how on earth I'm supposed to get the rest, I have no clue.
Pattern matching.
I watched a CNN story (or something) where the interviewer sat down with one of those big, obnoxious desktop calculators and asked her to solve something comparatively mundane like 63 * 127. She [Shakuntala Devi] did not look amused.
Multiplied by itself 22 times* FTFY
I actually timed it. it took me 1:50
If there were commas in there I'd have it in a heartbeat
Something about this story doesn't make sense. If the answer needed to be confirmed by a calculation later, who came up with the question in the first place? The answer is a whole number, so the 201-digit number can't have been picked at random. Someone would have had to raise 546,372,891 to the 23rd power in the first place to ask her the question.
I almost forgot how to do divisions the other day
Processing it? Hell, I couldn't even hold half of that number in short term memory long enough to even just repeat it back.
The answer is 546372891.
I saw the number and I was like, "that isn't so big." Then I went to select it for copy/paste and watched the number grow...exponentially.
I'm going to make a mental note of this story so that next time I meet a sexist dickwad who tells me women can't math, ( believe me,those dipshits exist,especially if you're over 45) I can use her as an example of why they're full of shit.
yeah this one genius will prove all those sexist bastards wrong! /s
Well, in their defence, statistically, men perform better at mathematics, formal logic and lifting things, and women perform better at almost everything else.
But these are observations about the general tendencies of several billion people, and very far from a hard rule.
I struggle with basic math on more occasions than I care to admit.
I don't have enough memory capacity to consciously recollect that, but I will remember it if I read it all.
That's why people in high school stopped showing me pieces of ID, like their Social Security number.
I didn't realize I had to scroll to see the whole number... I don't even...